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Simplify the following decimal fractions to the form a/b where a; b ∈ Z and b ≠ 0. Leave the answer in their simplest form.

Mathematics

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here are the solutions to Question 1:

1.1 Convert the following decimal fractions to the form ab\frac{a}{b} where a,b∈Za, b \in \mathbb{Z} and b≠0b \neq 0. Leave the answer in their simplest form.

1.1.1 0.58

  1. Write the decimal as a fraction over a power of 10.

    0.58=581000.58 = \frac{58}{100}
  2. Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 2.

    =58÷2100÷2=2950= \frac{58 \div 2}{100 \div 2} = \frac{29}{50}

    The simplified fraction is 2950\boxed{\mathbf{\frac{29}{50}}}.

    1.1.2 2.14

  3. Separate the whole number and the decimal part.

    2.14=2+0.142.14 = 2 + 0.14
  4. Convert the decimal part to a fraction and simplify.

    0.14=14100=14÷2100÷2=7500.14 = \frac{14}{100} = \frac{14 \div 2}{100 \div 2} = \frac{7}{50}
  5. Add the whole number and the simplified fraction.

    2+750=10050+750=107502 + \frac{7}{50} = \frac{100}{50} + \frac{7}{50} = \frac{107}{50}

    The simplified fraction is 10750\boxed{\mathbf{\frac{107}{50}}}.

    1.1.3 0.375

  6. Write the decimal as a fraction over a power of 10.

    0.375=37510000.375 = \frac{375}{1000}
  7. Simplify the fraction by dividing the numerator and denominator by their greatest common divisor.

    375÷1251000÷125=38\frac{375 \div 125}{1000 \div 125} = \frac{3}{8}

    The simplified fraction is 38\boxed{\mathbf{\frac{3}{8}}}.

    1.2 Simplify the following by using the laws of exponents and leave answers with positive exponents and in surd form where applicable:

    1.2.1 (81a316a−1)−32\left(\frac{81a^3}{16a^{-1}}\right)^{-\frac{3}{2}}

  8. Simplify the expression inside the parenthesis using exponent rules (am/an=am−na^m/a^n = a^{m-n}).

    (8116a3−(−1))−32=(8116a4)−32\left(\frac{81}{16} a^{3-(-1)}\right)^{-\frac{3}{2}} = \left(\frac{81}{16} a^4\right)^{-\frac{3}{2}}
  9. Apply the negative exponent by inverting the base.

    =(1681a4)32= \left(\frac{16}{81a^4}\right)^{\frac{3}{2}}
  10. Apply the fractional exponent, which means taking the square root first, then cubing the result.

    =(1681a4)3=(1681a4)3= \left(\sqrt{\frac{16}{81a^4}}\right)^3 = \left(\frac{\sqrt{16}}{\sqrt{81a^4}}\right)^3
  11. Calculate the square roots.

    =(49a2)3= \left(\frac{4}{9a^2}\right)^3
  12. Cube the expression.

    =43(9a2)3=6493(a2)3=64729a6= \frac{4^3}{(9a^2)^3} = \frac{64}{9^3 (a^2)^3} = \frac{64}{729a^6}

    The simplified expression is 64729a6\boxed{\mathbf{\frac{64}{729a^6}}}.

    1.2.2 x2y3×x3y4(2x−3y)2+4x2y3\frac{x^2y^3 \times x^3y^4}{(2x^{-3}y)^2} + \sqrt{4x^2y^3}

  13. Simplify the first term (the fraction) using exponent rules.

    x2y3×x3y4(2x−3y)2=x2+3y3+422(x−3)2y2=x5y74x−6y2\frac{x^2y^3 \times x^3y^4}{(2x^{-3}y)^2} = \frac{x^{2+3}y^{3+4}}{2^2(x^{-3})^2y^2} = \frac{x^5y^7}{4x^{-6}y^2}
  14. Continue simplifying the fraction.

    =14x5−(−6)y7−2=14x11y5= \frac{1}{4} x^{5-(-6)} y^{7-2} = \frac{1}{4} x^{11} y^5
  15. Simplify the second term (the surd).

    Assume x≥0x \ge 0 for x2=x\sqrt{x^2}=x.

    4x2y3=4⋅x2⋅y2⋅y=2xyy\sqrt{4x^2y^3} = \sqrt{4} \cdot \sqrt{x^2} \cdot \sqrt{y^2 \cdot y} = 2xy\sqrt{y}
  16. Combine the simplified terms.

    14x11y5+2xyy\frac{1}{4} x^{11} y^5 + 2xy\sqrt{y}

    The simplified expression is 14x11y5+2xyy\boxed{\mathbf{\frac{1}{4} x^{11} y^5 + 2xy\sqrt{y}}}.

    1.3 Simplify the following by using surd laws. Leave answer in a surd form.

    75+12+108147\frac{\sqrt{75}+\sqrt{12}+\sqrt{108}}{\sqrt{147}}
  17. Simplify each surd in the numerator by finding perfect square factors.

    75=25×3=53\sqrt{75} = \sqrt{25 \times 3} = 5\sqrt{3} 12=4×3=23\sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3} 108=36×3=63\sqrt{108} = \sqrt{36 \times 3} = 6\sqrt{3}
  18. Simplify the surd in the denominator.

    147=49×3=73\sqrt{147} = \sqrt{49 \times 3} = 7\sqrt{3}
  19. Substitute the simplified surds back into the expression.

    53+23+6373\frac{5\sqrt{3}+2\sqrt{3}+6\sqrt{3}}{7\sqrt{3}}
  20. Combine the like terms in the numerator.

    =(5+2+6)373=13373= \frac{(5+2+6)\sqrt{3}}{7\sqrt{3}} = \frac{13\sqrt{3}}{7\sqrt{3}}
  21. Cancel out the common factor 3\sqrt{3}.

    =137= \frac{13}{7}

    The simplified expression is 137\boxed{\mathbf{\frac{13}{7}}}.

    1.4 Simplify the following expression by rationalising the denominator.

    2−33−2\frac{2-\sqrt{3}}{3-\sqrt{2}}
  22. Multiply the numerator and the denominator by the conjugate of the denominator, which is 3+23+\sqrt{2}.

    2−33−2×3+23+2\frac{2-\sqrt{3}}{3-\sqrt{2}} \times \frac{3+\sqrt{2}}{3+\sqrt{2}}
  23. Expand the numerator using the distributive property (FOIL).

    (2−3)(3+2)=2(3)+2(2)−3(3)−3(2)(2-\sqrt{3})(3+\sqrt{2}) = 2(3) + 2(\sqrt{2}) - \sqrt{3}(3) - \sqrt{3}(\sqrt{2}) =6+22−33−6= 6 + 2\sqrt{2} - 3\sqrt{3} - \sqrt{6}
  24. Expand the denominator using the difference of squares formula (a−b)(a+b)=a2−b2(a-b)(a+b)=a^2-b^2.

    (3−2)(3+2)=32−(2)2=9−2=7(3-\sqrt{2})(3+\sqrt{2}) = 3^2 - (\sqrt{2})^2 = 9 - 2 = 7
  25. Combine the simplified numerator and denominator.

    =6+22−33−67= \frac{6 + 2\sqrt{2} - 3\sqrt{3} - \sqrt{6}}{7}

    The simplified expression is 6+22−33−67\boxed{\mathbf{\frac{6 + 2\sqrt{2} - 3\sqrt{3} - \sqrt{6}}{7}}}.

    1.5 Given: At=A0(1+r100)nA_t = A_0 \left(1 + \frac{r}{100}\right)^n

    1.5.1 Make "r" the subject of the formula.

  26. Divide both sides by A0A_0.

    AtA0=(1+r100)n\frac{A_t}{A_0} = \left(1 + \frac{r}{100}\right)^n
  27. Take the nn-th root of both sides.

    AtA0n=1+r100\sqrt[n]{\frac{A_t}{A_0}} = 1 + \frac{r}{100}
  28. Subtract 1 from both sides.

    AtA0n−1=r100\sqrt[n]{\frac{A_t}{A_0}} - 1 = \frac{r}{100}
  29. Multiply both sides by 100.

    r=100(AtA0n−1)r = 100 \left(\sqrt[n]{\frac{A_t}{A_0}} - 1\right)

    The formula with rr as the subject is r=100(AtA0n−1)\boxed{\mathbf{r = 100 \left(\sqrt[n]{\frac{A_t}{A_0}} - 1\right)}}.

    1.5.2 Determine the value of r if n=4, A0=3000A_0=3000 and At=4200A_t=4200.

  30. Use the formula derived in 1.5.1.

    r=100(AtA0n−1)r = 100 \left(\sqrt[n]{\frac{A_t}{A_0}} - 1\right)
  31. Substitute the given values n=4n=4, A0=3000A_0=3000, and At=4200A_t=4200.

    r=100(420030004−1)r = 100 \left(\sqrt[4]{\frac{4200}{3000}} - 1\right)
  32. Simplify the fraction inside the root.

    r=100(42304−1)=100(754−1)r = 100 \left(\sqrt[4]{\frac{42}{30}} - 1\right) = 100 \left(\sqrt[4]{\frac{7}{5}} - 1\right) r=100(1.44−1)r = 100 \left(\sqrt[4]{1.4} - 1\right)
  33. Calculate the fourth root and then the value of rr.

    r≈100(1.08775−1)r \approx 100 (1.08775 - 1) r≈100(0.08775)r \approx 100 (0.08775) r≈8.775r \approx 8.775

    The value of rr is approximately 8.775\boxed{\mathbf{8.775}}.

    (Question 1.6 was addressed in a previous message.)

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