Simplify the following expression: sqrt((27x4)/(3)) + 3/(27) - sqrt((x5)/(x))

$$\sqrt{\frac{27x^4}{3}} = \sqrt{9x^4}$$ $$\sqrt{9x^4} = \sqrt{9} \cdot \sqrt{x^4} = 3x^2$$

$$\sqrt[3]{\frac{3x^6}{27}} = \sqrt[3]{\frac{x^6}{9}}$$ $$\sqrt[3]{\frac{x^6}{9}} = \frac{\sqrt[3]{x^6}}{\sqrt[3]{9}} = \frac{x^2}{\sqrt[3]{9}}$$

To rationalize the denominator, multiply the numerator and denominator by $\sqrt[3]{3}$:

$$\frac{x^2}{\sqrt[3]{9}} \cdot \frac{\sqrt[3]{3}}{\sqrt[3]{3}} = \frac{x^2\sqrt[3]{3}}{\sqrt[3]{27}} = \frac{x^2\sqrt[3]{3}}{3}$$

$$\sqrt{\frac{x^5}{x}} = \sqrt{x^{5-1}} = \sqrt{x^4}$$ $$\sqrt{x^4} = x^2$$

$$3x^2 + \frac{x^2\sqrt[3]{3}}{3} - x^2$$

Combine the like terms ($3x^2 - x^2$):

$$(3x^2 - x^2) + \frac{x^2\sqrt[3]{3}}{3} = 2x^2 + \frac{x^2\sqrt[3]{3}}{3}$$

The final answer is $2x^2 + \frac{x^2\sqrt[3]{3}}{3}$.