This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Eyi ni bi a ṣe le yanju awọn iṣoro wọnyi: 1) Step 1: Lo ofin awọn agbara (exponents) ti o sọ pe nigba ti o ba pin awọn nọmba pẹlu ipilẹ kanna, o yọ awọn agbara wọn kuro. 6^106^4 = 6^10-4 Step 2: Yọ awọn agbara kuro. 6^10-4 = 6^6 Step 3: Ṣe iṣiro iye naa. 6^6 = 6 × 6 × 6 × 6 × 6 × 6 = 46656 Idahun: 46656 2) Step 1: Lo ofin awọn agbara ti o sọ pe nigba ti o ba pin awọn oniyipada pẹlu ipilẹ kanna, o yọ awọn agbara wọn kuro. x^12x^3 = x^12-3 Step 2: Yọ awọn agbara kuro. x^12-3 = x^9 Idahun: x^9 3) Step 1: Pin awọn nọmba ati awọn oniyipada lọtọ. (24m^2n^5)/(4m^3n^2) = ((24)/(4)) ((m^2)/(m^3)) ((n^5)/(n^2)) Step 2: Ṣe iṣiro apakan nọmba ati lo ofin awọn agbara fun awọn oniyipada. 6 · m^2-3 · n^5-2 Step 3: Yọ awọn agbara kuro. 6 · m^-1 · n^3 Step 4: Tun kọ m^-1 bi (1)/(m). (6n^3)/(m) Idahun: (6n^3)/(m) 4) Step 1: Kọkọ yanju ohun ti o wa ninu akọmọ. (5-3)^4 = (2)^4 Step 2: Gbe abajade si agbara ti 4. 2^4 = 2 × 2 × 2 × 2 = 16 Idahun: 16 5) Abala y^22 jẹ gbolohun ọrọ kan ti o duro nikan. Ko si iṣẹ-ṣiṣe ti o han lati yanju pẹlu rẹ. Idahun: y^22 Mándame la siguiente 📸