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Simplify the following expressions involving exponents: a) x⁻³ / y⁻², b) 2xⁿ y4 / 2x^(n-1) y3, c) ((1/2)⁻²)⁻³, d) (32^(3a+2)) / (8^(a+b))

Mathematics

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Answers

4 parts
a

y2x3\frac{y^2}{x^3}

b

xy

c

164\frac{1}{64}

d

212a−3b+102^{12a-3b+10}

Step-by-step solution

12 steps

Here are the simplifications:

Part a· 1 step

  1. Apply the negative exponent rule a−n=1ana^{-n} = \frac{1}{a^n}.

    x−3y−2=y2x3\frac{x^{-3}}{y^{-2}} = \frac{y^2}{x^3}

    The expression is already simplified.

    y2x3\boxed{\frac{y^2}{x^3}}

Part bxy

  1. Separate the terms and apply the exponent rule aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    2xny42xn−1y3=(22)(xnxn−1)(y4y3)\frac{2x^n y^4}{2x^{n-1} y^3} = \left(\frac{2}{2}\right) \left(\frac{x^n}{x^{n-1}}\right) \left(\frac{y^4}{y^3}\right)
  2. Simplify each part.

    1⋅xn−(n−1)⋅y4−3=xn−n+1⋅y11 \cdot x^{n-(n-1)} \cdot y^{4-3} = x^{n-n+1} \cdot y^1
  3. Combine the terms.

    x1y1=xyx^1 y^1 = xy xy\boxed{xy}

Part c

164\frac{1}{64}

  1. Simplify the innermost exponent using (ab)−n=(ba)n\left(\frac{a}{b}\right)^{-n} = \left(\frac{b}{a}\right)^n.

    ((12)−2)−3=(22)−3\left(\left(\frac{1}{2}\right)^{-2}\right)^{-3} = \left(2^2\right)^{-3}
  2. Simplify the term inside the parenthesis.

    (4)−3(4)^{-3}
  3. Apply the negative exponent rule a−n=1ana^{-n} = \frac{1}{a^n}.

    4−3=1434^{-3} = \frac{1}{4^3}
  4. Calculate the final value.

    14×4×4=164\frac{1}{4 \times 4 \times 4} = \frac{1}{64} 164\boxed{\frac{1}{64}}

Part d

212a−3b+102^{12a-3b+10}

  1. Express the bases 32 and 8 as powers of 2.

    32=2532 = 2^5 8=238 = 2^3

    Substitute these into the expression.

    (25)3a+2(23)a+b\frac{(2^5)^{3a+2}}{(2^3)^{a+b}}
  2. Apply the exponent rule (am)n=am×n(a^m)^n = a^{m \times n}.

    25(3a+2)23(a+b)=215a+1023a+3b\frac{2^{5(3a+2)}}{2^{3(a+b)}} = \frac{2^{15a+10}}{2^{3a+3b}}
  3. Apply the exponent rule aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    2(15a+10)−(3a+3b)2^{(15a+10) - (3a+3b)}
  4. Simplify the exponent.

    215a+10−3a−3b=212a−3b+102^{15a+10-3a-3b} = 2^{12a-3b+10} 212a−3b+10\boxed{2^{12a-3b+10}}
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