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Find the square root of 2.56 and 7.29 using the long division method.

Mathematics

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Answers

4 parts
i

1.6\text{1.6}

ii

2.7\text{2.7}

iii

7.2\text{7.2}

v

5.6\text{5.6}

i) 2.56

Step 1: Group the digits in pairs from the decimal point. For 2.56, the pairs are 2 and 56.

Step 2: Find the largest integer whose square is less than or equal to the first pair (2). This is 1 (12=11^2 = 1). Write 1 as the quotient and subtract 1 from 2.

Step 3: Bring down the next pair (56) and place the decimal point in the quotient. The new dividend is 156. Double the current quotient (1) to get 2. Find a digit 'x' such that 2x×x≤1562x \times x \le 156. Here, 26×6=15626 \times 6 = 156.

1.61)2.56‾−1.0026)156‾−1560\begin{array}{r} 1.6 \\[-3pt] 1 \overline{\smash{)} 2.56} \\[-3pt] -1 \phantom{.00} \\[-3pt] \hline 26 \overline{\smash{)} 156} \\[-3pt] -156 \\[-3pt] \hline 0 \end{array}

The square root of 2.56 is 1.6\boxed{\text{1.6}}.

ii) 7.29

Step 1: Group the digits in pairs from the decimal point. For 7.29, the pairs are 7 and 29.

Step 2: Find the largest integer whose square is less than or equal to the first pair (7). This is 2 (22=42^2 = 4). Write 2 as the quotient and subtract 4 from 7.

Step 3: Bring down the next pair (29) and place the decimal point in the quotient. The new dividend is 329. Double the current quotient (2) to get 4. Find a digit 'x' such that 4x×x≤3294x \times x \le 329. Here, 47×7=32947 \times 7 = 329.

2.72)7.29‾−4.0047)329‾−3290\begin{array}{r} 2.7 \\[-3pt] 2 \overline{\smash{)} 7.29} \\[-3pt] -4 \phantom{.00} \\[-3pt] \hline 47 \overline{\smash{)} 329} \\[-3pt] -329 \\[-3pt] \hline 0 \end{array}

The square root of 7.29 is 2.7\boxed{\text{2.7}}.

iii) 51.84

Step 1: Group the digits in pairs from the decimal point. For 51.84, the pairs are 51 and 84.

Step 2: Find the largest integer whose square is less than or equal to the first pair (51). This is 7 (72=497^2 = 49). Write 7 as the quotient and subtract 49 from 51.

Step 3: Bring down the next pair (84) and place the decimal point in the quotient. The new dividend is 284. Double the current quotient (7) to get 14. Find a digit 'x' such that 14x×x≤28414x \times x \le 284. Here, 142×2=284142 \times 2 = 284.

7.27)51.84‾−49.00142)284‾−2840\begin{array}{r} 7.2 \\[-3pt] 7 \overline{\smash{)} 51.84} \\[-3pt] -49 \phantom{.00} \\[-3pt] \hline 142 \overline{\smash{)} 284} \\[-3pt] -284 \\[-3pt] \hline 0 \end{array}

The square root of 51.84 is 7.2\boxed{\text{7.2}}.

v) 31.36

Step 1: Group the digits in pairs from the decimal point. For 31.36, the pairs are 31 and 36.

Step 2: Find the largest integer whose square is less than or equal to the first pair (31). This is 5 (52=255^2 = 25). Write 5 as the quotient and subtract 25 from 31.

Step 3: Bring down the next pair (36) and place the decimal point in the quotient. The new dividend is 636. Double the current quotient (5) to get 10. Find a digit 'x' such that 10x×x≤63610x \times x \le 636. Here, 106×6=636106 \times 6 = 636.

5.65)31.36‾−25.00106)636‾−6360\begin{array}{r} 5.6 \\[-3pt] 5 \overline{\smash{)} 31.36} \\[-3pt] -25 \phantom{.00} \\[-3pt] \hline 106 \overline{\smash{)} 636} \\[-3pt] -636 \\[-3pt] \hline 0 \end{array}

The square root of 31.36 is 5.6\boxed{\text{5.6}}.

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