In an army camp there is sufficient food for 120 cadets for 24 days. If 48 cadets leave the camp, how long would the food last?

Mathematics
In an army camp there is sufficient food for 120 cadets for 24 days. If 48 cadets leave the camp, how long would the food last?

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Answer

1+32\dfrac{1 + \sqrt{3}}{2}

Section A, Question 1

Step 1: Standard value of sinπ3\sin\frac{\pi}{3}.

sinπ3=32\sin\frac{\pi}{3} = \frac{\sqrt{3}}{2}

Step 2: Standard value of cosπ3\cos\frac{\pi}{3}.

cosπ3=12\cos\frac{\pi}{3} = \frac{1}{2}

Step 3: Add the values.

sinπ3+cosπ3=32+12=1+32\sin\frac{\pi}{3} + \cos\frac{\pi}{3} = \frac{\sqrt{3}}{2} + \frac{1}{2} = \frac{1 + \sqrt{3}}{2}

\dfrac{1 + \sqrt{3}{2}}

Section A, Question 2 (Men work problem)

Step 1: Total man-days required for the wall.

30 men ×\times 20 days = 600 man-days.

Step 2: Days taken by 25 men.

Days = 60025=24\frac{600}{25} = 24 days.

24 \text{ days}

Section B, Question 1 (Probability of two tails)

Step 1: Probability of tails on single fair coin toss.

P(tail)=12P(tail) = \frac{1}{2}

Step 2

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Quick Answer

Section A, Question 1 Step 1: Standard value of ()/(3). ()/(3) = sqrt(3)2 Step 2: Standard value of ()/(3).

In an army camp there is sufficient food for 120 cadets for 24 days. If 48 cadets leave the camp, how long would the food last?
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Section A, Question 1 Step 1: Standard value of ()/(3). ()/(3) = sqrt(3)2 Step 2: Standard value of ()/(3). ()/(3) = (1)/(2) Step 3: Add the values. ()/(3) + ()/(3) = sqrt(3)2 + (1)/(2) = 1 + sqrt(3)2 1 + sqrt(3)2 Section A, Question 2 (Men work problem) Step 1: Total man-days required for the wall. 30 men × 20 days = 600 man-days. Step 2: Days taken by 25 men. Days = (600)/(25) = 24 days. 24 days Section B, Question 1 (Probability of two tails) Step 1: Probability of tails on single fair coin toss. P(tail) = (1)/(2) Step 2