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Substitute the value of a into the expression a - (1)/(a).

Mathematics

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Answer

1163\frac{11}{6}\sqrt{3}

Step-by-step solution

5 steps
  1. Substitute the value of aa into the expression a−1aa - \frac{1}{a}.

    a−1a=23−123a - \frac{1}{a} = 2\sqrt{3} - \frac{1}{2\sqrt{3}}
  2. Rationalize the denominator of the second term.

    123=123×33=32×3=36\frac{1}{2\sqrt{3}} = \frac{1}{2\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{2 \times 3} = \frac{\sqrt{3}}{6}
  3. Substitute the rationalized term back into the expression.

    23−362\sqrt{3} - \frac{\sqrt{3}}{6}
  4. Combine the terms by finding a common denominator.

    23−36=1236−362\sqrt{3} - \frac{\sqrt{3}}{6} = \frac{12\sqrt{3}}{6} - \frac{\sqrt{3}}{6} =123−36= \frac{12\sqrt{3} - \sqrt{3}}{6} =(12−1)36= \frac{(12-1)\sqrt{3}}{6} =1136= \frac{11\sqrt{3}}{6}
  5. Express the result in the form x+y3x+y\sqrt{3}.

    1136=0+1163\frac{11\sqrt{3}}{6} = 0 + \frac{11}{6}\sqrt{3}

    Here, x=0x=0 and y=116y=\frac{11}{6}.

    The expression a−1aa - \frac{1}{a} in the form x+y3x+y\sqrt{3} is 1163\boxed{\frac{11}{6}\sqrt{3}}.

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