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Subtract the following octal numbers: 737618 - 727778.

Mathematics

ScanSolve AI Answer

Answer

7628762_8

Step-by-step solution

5 steps

To subtract numbers in base 8, we perform column-by-column subtraction, borrowing from the left when necessary. When we borrow 1 from a column, it adds 8 to the value of the digit in the current column.

We need to calculate 737618−72777873761_8 - 72777_8.

  1. Subtract the rightmost column (units place).

    We have 18−781_8 - 7_8. Since 1<71 < 7, we borrow from the 686_8 in the next column.
    The 686_8 becomes 585_8. The 181_8 becomes 1+8=9101+8 = 9_{10}.
    Now, 910−710=2109_{10} - 7_{10} = 2_{10}. So the units digit is 282_8.

  2. Subtract the next column (eights place).

    We now have 58−785_8 - 7_8. Since 5<75 < 7, we borrow from the 787_8 in the next column.
    The 787_8 becomes 686_8. The 585_8 becomes 5+8=13105+8 = 13_{10}.
    Now, 1310−710=61013_{10} - 7_{10} = 6_{10}. So the eights digit is 686_8.

  3. Subtract the next column (828^2 place).

    We now have 68−786_8 - 7_8. Since 6<76 < 7, we borrow from the 383_8 in the next column.
    The 383_8 becomes 282_8. The 686_8 becomes 6+8=14106+8 = 14_{10}.
    Now, 1410−710=71014_{10} - 7_{10} = 7_{10}. So the 828^2 digit is 787_8.

  4. Subtract the next column (838^3 place).

    We now have 28−282_8 - 2_8.
    28−28=082_8 - 2_8 = 0_8. So the 838^3 digit is 080_8.

  5. Subtract the leftmost column (848^4 place).

    We have 78−787_8 - 7_8.
    78−78=087_8 - 7_8 = 0_8. So the 848^4 digit is 080_8.

    Combining the results from right to left:

    737618−727778007628\begin{array}{cccccc} & 7 & 3 & 7 & 6 & 1_8 \\ - & 7 & 2 & 7 & 7 & 7_8 \\ \hline & 0 & 0 & 7 & 6 & 2_8 \\ \end{array}

    The result is 00762800762_8, which simplifies to 7628762_8.

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