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Calculate the sum, mean, and sum of squares for each group.

Mathematics

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II. Calculate the F-value.

  1. Calculate the sum, mean, and sum of squares for each group.

    • Agric. Education (G1G_1): Scores (8, 5, 5, 9, 7, 8, 9, 5, 6, 8) n1=10n_1 = 10 ∑x1=70\sum x_1 = 70 xˉ1=7010=7\bar{x}_1 = \frac{70}{10} = 7 ∑x12=514\sum x_1^2 = 514
    • Business Education (G2G_2): Scores (7, 6, 6, 4, 8, 3, 6, 5, 7, 4) n2=10n_2 = 10 ∑x2=56\sum x_2 = 56 xˉ2=5610=5.6\bar{x}_2 = \frac{56}{10} = 5.6 ∑x22=336\sum x_2^2 = 336
    • Industrial Technical Education (G3G_3): Scores (5, 4, 5, 6, 3, 5, 4, 7, 3, 4) n3=10n_3 = 10 ∑x3=46\sum x_3 = 46 xˉ3=4610=4.6\bar{x}_3 = \frac{46}{10} = 4.6 ∑x32=230\sum x_3^2 = 230

    Overall: N=n1+n2+n3=10+10+10=30N = n_1 + n_2 + n_3 = 10 + 10 + 10 = 30
    Grand Sum (∑x\sum x) = 70+56+46=17270 + 56 + 46 = 172
    Grand Sum of Squares (∑x2\sum x^2) = 514+336+230=1080514 + 336 + 230 = 1080

  2. Calculate the Correction Factor (CF), Total Sum of Squares (SST), Sum of Squares Between Groups (SSB), and Sum of Squares Within Groups (SSW).

    • Correction Factor: CF=(∑x)2N=(172)230=2958430=986.1333CF = \frac{(\sum x)^2}{N} = \frac{(172)^2}{30} = \frac{29584}{30} = 986.1333
    • Total Sum of Squares: SST=∑x2−CF=1080−986.1333=93.8667SST = \sum x^2 - CF = 1080 - 986.1333 = 93.8667
    • Sum of Squares Between Groups: SSB=((∑x1)2n1+(∑x2)2n2+(∑x3)2n3)−CFSSB = \left(\frac{(\sum x_1)^2}{n_1} + \frac{(\sum x_2)^2}{n_2} + \frac{(\sum x_3)^2}{n_3}\right) - CF SSB=(70210+56210+46210)−986.1333SSB = \left(\frac{70^2}{10} + \frac{56^2}{10} + \frac{46^2}{10}\right) - 986.1333 SSB=(490+313.6+211.6)−986.1333=1015.2−986.1333=29.0667SSB = (490 + 313.6 + 211.6) - 986.1333 = 1015.2 - 986.1333 = 29.0667
    • Sum of Squares Within Groups: SSW=SST−SSB=93.8667−29.0667=64.8SSW = SST - SSB = 93.8667 - 29.0667 = 64.8
  3. Calculate the degrees of freedom.

    • Degrees of freedom between groups (dfBdf_B) = k−1=3−1=2k - 1 = 3 - 1 = 2
    • Degrees of freedom within groups (dfWdf_W) = N−k=30−3=27N - k = 30 - 3 = 27
  4. Calculate the Mean Square Between Groups (MSB) and Mean Square Within Groups (MSW).

    • Mean Square Between Groups: MSB=SSBdfB=29.06672=14.53335MSB = \frac{SSB}{df_B} = \frac{29.0667}{2} = 14.53335
    • Mean Square Within Groups: MSW=SSWdfW=64.827=2.4MSW = \frac{SSW}{df_W} = \frac{64.8}{27} = 2.4
  5. Calculate the F-value.

    F=MSBMSW=14.533352.4=6.0555625F = \frac{MSB}{MSW} = \frac{14.53335}{2.4} = 6.0555625

    The calculated F-value is 6.06\boxed{6.06}.

    III. What is the F-table value?

  6. Determine the critical F-value from the F-distribution table.

    Using α=0.05\alpha = 0.05, df1=dfB=2df_1 = df_B = 2, and df2=dfW=27df_2 = df_W = 27:
    The F-table value is 3.35\boxed{3.35}.

    IV. What is your decision based on the results?

  7. Compare the calculated F-value with the F-table value.

    Since the calculated F-value (6.06) is greater than the critical F-table value (3.35), we reject the null hypothesis.

    V. What is your conclusion?

  8. State the conclusion.

    There is sufficient evidence to conclude that there is a significant difference in the mean quiz scores among the students in Agric. Education, Business Education, and Industrial Technical Education departments at the 0.05 level of significance.

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