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Sunita buys 5 kg of rice at Rs 90 per kg and 2 kg of sugar at Rs 70 per kg. Write a mathematical expression and simplify it to find the total cost and the change she gets back if she pays with Rs 1000

Mathematics

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16 steps

Here are the solutions for the remaining questions.

Part c(i)· 3 steps

Write a mathematical expression and simplify it to find the total cost of these two items.

Sunita buys 5 kg of rice at Rs 90 per kg and 2 kg of sugar at Rs 70 per kg.

  1. Calculate the cost of rice.

    Cost of rice =5 kg×Rs 90/kg=Rs 450= 5 \text{ kg} \times \text{Rs } 90/\text{kg} = \text{Rs } 450

  2. Calculate the cost of sugar (assuming Rs 70 per kg).

    Cost of sugar =2 kg×Rs 70/kg=Rs 140= 2 \text{ kg} \times \text{Rs } 70/\text{kg} = \text{Rs } 140

  3. Write the mathematical expression for the total cost and simplify.

    Total cost =(5×90)+(2×70)= (5 \times 90) + (2 \times 70)
    Total cost =450+140=590= 450 + 140 = 590
    The total cost is Rs 590.

    Rs 590\boxed{\text{Rs } 590}

Part c(ii)· 13 steps

If she gives a 1000 rupees note to the shopkeeper, how much does the shopkeeper return to her?

  1. Subtract the total cost from the amount paid.

    Change =1000−590=410= 1000 - 590 = 410
    The shopkeeper returned Rs 410.

    Rs 410\boxed{\text{Rs } 410}

    d) On a day, there were 27 students present in class six. 16 of them are girls and the rest were boys. If only 3 boys were absent on that day, represent the information by a mathematical expression and find the number of boys in class six.

  2. Find the total number of boys present.

    Total boys present =27−16=11= 27 - 16 = 11

  3. Add the absent boys to find the total number of boys in class six.

    Total boys in class =(27−16)+3= (27 - 16) + 3
    Total boys in class =11+3=14= 11 + 3 = 14
    The number of boys in class six is 14.

    14\boxed{14}

    9. a) Let's make any four your own mixed expressions using all (+,−,×,÷)(+, -, \times, \div) in each expression. Simplify them and get answers.

    Expression 1:

    10+5×2−8÷410 + 5 \times 2 - 8 \div 4
  4. Perform multiplication and division from left to right.

    10+10−210 + 10 - 2
  5. Perform addition and subtraction from left to right.

    20−2=1820 - 2 = 18 18\boxed{18}

    Expression 2:

    (20−5)÷3+7×2(20 - 5) \div 3 + 7 \times 2
  6. Perform operations inside parentheses.

    15÷3+7×215 \div 3 + 7 \times 2
  7. Perform division and multiplication from left to right.

    5+145 + 14
  8. Perform addition.

    1919 19\boxed{19}

    Expression 3:

    15×2−(10+4)÷215 \times 2 - (10 + 4) \div 2
  9. Perform operations inside parentheses.

    15×2−14÷215 \times 2 - 14 \div 2
  10. Perform multiplication and division from left to right.

    30−730 - 7
  11. Perform subtraction.

    2323 23\boxed{23}

    Expression 4:

    100÷10+5−2×3100 \div 10 + 5 - 2 \times 3
  12. Perform division and multiplication from left to right.

    10+5−610 + 5 - 6
  13. Perform addition and subtraction from left to right.

    15−6=915 - 6 = 9 9\boxed{9}

    9. b) Let's rewrite these simplifications and find the mistakes. Then, show the simplification in the correct way.

    Box 1:
    Given:

    35−10+535 - 10 + 5 =35−15= 35 - 15 =20= 20

    Mistake: Addition was performed before subtraction. Operations of the same precedence (addition and subtraction) should be done from left to right.
    Correct simplification:

    35−10+535 - 10 + 5 =25+5= 25 + 5 =30= 30 30\boxed{30}

    Box 2:
    Given:

    27−6−427 - 6 - 4 =27−2= 27 - 2 =25= 25

    Mistake: The second subtraction (6−46-4) was performed before the first subtraction (27−627-6). Subtraction operations should be done from left to right.
    Correct simplification:

    27−6−427 - 6 - 4 =21−4= 21 - 4 =17= 17 17\boxed{17}

    Box 3:
    Given:

    9+3×29 + 3 \times 2 =12×2= 12 \times 2 =24= 24

    Mistake: Addition was performed before multiplication. Multiplication has higher precedence than addition.
    Correct simplification:

    9+3×29 + 3 \times 2 =9+6= 9 + 6 =15= 15 15\boxed{15}

    Box 4:
    Given:

    18−5×318 - 5 \times 3 =13×3= 13 \times 3 =39= 39

    Mistake: Subtraction was performed before multiplication. Multiplication has higher precedence than subtraction.
    Correct simplification:

    18−5×318 - 5 \times 3 =18−15= 18 - 15 =3= 3 3\boxed{3}

    Box 5: (Based on the visible part, assuming the expression is 40÷5+340 \div 5 + 3)
    Given:

    40÷5+340 \div 5 + 3 =8+3= 8 + 3 =11= 11

    This simplification is correct. Division was performed before addition, following the order of operations.

    11\boxed{11}
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