This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Answer
10n + 3
Here are the solutions for each part of question 1:
a) Step 1: Find the common difference. The terms are . The difference between consecutive terms is , , . The common difference is .
Step 2: Determine the term. Since the common difference is , the term will be of the form . For , the term is . So, . Thus, the term is .
Step 3: Calculate the term. Substitute into the term formula: .
The term is: The term is:
b) Step 1: Find the common difference. The terms are . The difference between consecutive terms is , , . The common difference is .
Step 2: Determine the term. Since the common difference is , the term will be of the form . For , the term is . So, . Thus, the term is .
Step 3: Calculate the term. Substitute into the term formula: .
The term is: The term is:
c) Step 1: Find the common difference. The terms are . The difference between consecutive terms is , , . The common difference is .
Step 2: Determine the term. Since the common difference is , the term will be of the form . For , the term is . So, . Thus, the term is .
Step 3: Calculate the term. Substitute into the term formula: .
The term is: The term is:
d) Step 1: Find the common difference. The terms are . The difference between consecutive terms is , , . The common difference is .
Step 2: Determine the term. Since the common difference is , the term will be of the form . For , the term is . So, . Thus, the term is .
Step 3: Calculate the term. Substitute into the term formula: .
The term is: The term is:
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a) Step 1: Find the common difference. The terms are 13, 23, 33, 43.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.