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What is the area of a triangle with a base of 18cm and a height of 7cm? 2. Find the Perimeter of a circle with a ridus of 5cm. 3. Find the area of a circle with radius of 6cm. 4. Calculate the Volume for each of the cubes, (a) edge length 2cm. b. edge length 4cm. 5. Find the area of a square 3cm.

Mathematics

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Answers

2 parts
a

8 cm3\text{8 cm}^3

b

64 cm3\text{64 cm}^3

9 cm2\text{9 cm}^2

Step-by-step solution

7 steps

Here are the solutions to your math questions:

1. Area of a triangle

Step 1: Recall the formula for the area of a triangle.
The area of a triangle is given by:

A=12×base×heightA = \frac{1}{2} \times \text{base} \times \text{height}

Step 2: Substitute the given values into the formula.
Given base =18 cm= 18 \text{ cm} and height =7 cm= 7 \text{ cm}.

A=12×18 cm×7 cmA = \frac{1}{2} \times 18 \text{ cm} \times 7 \text{ cm}

Step 3: Calculate the area.

A=9 cm×7 cmA = 9 \text{ cm} \times 7 \text{ cm} A=63 cm2A = 63 \text{ cm}^2

The area of the triangle is 63 cm2\boxed{\text{63 cm}^2}.

2. Perimeter of a circle

Step 1: Recall the formula for the perimeter (circumference) of a circle.
The circumference of a circle is given by:

C=2πrC = 2\pi r

where rr is the radius.

Step 2: Substitute the given radius into the formula.
Given radius r=5 cmr = 5 \text{ cm}.

C=2×π×5 cmC = 2 \times \pi \times 5 \text{ cm}

Step 3: Calculate the circumference.

C=10π cmC = 10\pi \text{ cm}

Using π≈3.14159\pi \approx 3.14159:

C≈10×3.14159 cmC \approx 10 \times 3.14159 \text{ cm} C≈31.4159 cmC \approx 31.4159 \text{ cm}

The perimeter of the circle is 10\picm≈31.42 cm\boxed{\text{10\pi cm} \approx \text{31.42 cm}}.

3. Area of a circle

Step 1: Recall the formula for the area of a circle.
The area of a circle is given by:

A=πr2A = \pi r^2

where rr is the radius.

Step 2: Substitute the given radius into the formula.
Given radius r=6 cmr = 6 \text{ cm}.

A=π×(6 cm)2A = \pi \times (6 \text{ cm})^2

Step 3: Calculate the area.

A=π×36 cm2A = \pi \times 36 \text{ cm}^2 A=36π cm2A = 36\pi \text{ cm}^2

Using π≈3.14159\pi \approx 3.14159:

A≈36×3.14159 cm2A \approx 36 \times 3.14159 \text{ cm}^2 A≈113.097 cm2A \approx 113.097 \text{ cm}^2

The area of the circle is 36\picm2≈113.10 cm2\boxed{\text{36\pi cm}^2 \approx \text{113.10 cm}^2}.

4. Volume for each of the cubes

Step 1: Recall the formula for the volume of a cube.
The volume of a cube is given by:

V=edge length3V = \text{edge length}^3

Part a· 2 steps

Edge length 2 cm

  1. Substitute the edge length into the formula.

    V=(2 cm)3V = (2 \text{ cm})^3
  2. Calculate the volume.

    V=2 cm×2 cm×2 cmV = 2 \text{ cm} \times 2 \text{ cm} \times 2 \text{ cm} V=8 cm3V = 8 \text{ cm}^3

    The volume of the cube is 8 cm3\boxed{\text{8 cm}^3}.

Part b

64 cm3\text{64 cm}^3

Edge length 4 cm

  1. Substitute the edge length into the formula.

    V=(4 cm)3V = (4 \text{ cm})^3
  2. Calculate the volume.

    V=4 cm×4 cm×4 cmV = 4 \text{ cm} \times 4 \text{ cm} \times 4 \text{ cm} V=64 cm3V = 64 \text{ cm}^3

    The volume of the cube is 64 cm3\boxed{\text{64 cm}^3}.

    5. Area of a square

  3. Recall the formula for the area of a square.

    The area of a square is given by:

    A=side length2A = \text{side length}^2
  4. Substitute the given side length into the formula.

    Given side length =3 cm= 3 \text{ cm}.

    A=(3 cm)2A = (3 \text{ cm})^2
  5. Calculate the area.

    A=3 cm×3 cmA = 3 \text{ cm} \times 3 \text{ cm} A=9 cm2A = 9 \text{ cm}^2

    The area of the square is 9 cm2\boxed{\text{9 cm}^2}.

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