This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Q9. Find the Volume of the triangular prism
a) The volume of a prism is given by the formula , where is the area of the base and is the length (or height) of the prism. For a triangular prism, the base is a triangle, and its area is .
Given: Base of the triangle () = Height of the triangle () = Length of the prism () =
Step 1: Calculate the area of the triangular base.
Step 2: Calculate the volume of the triangular prism. Answer: 1200 \text{ cm^3}
b) For question 9b, the problem asks for the volume of a triangular prism, but the accompanying diagram shows a rectangular prism. I will solve for a triangular prism, assuming the base of the triangle is , the height of the triangle is (derived from the square base shown in the diagram), and the length of the prism is .
Given (based on assumption for triangular prism): Base of the triangle () = Height of the triangle () = Length of the prism () =
Step 1: Calculate the area of the triangular base.
Step 2: Calculate the volume of the triangular prism. Answer: 384 \text{ in^3}
Q10. What is the Volume of a cone with a radius of 5 cm and a height of 8 cm? The volume of a cone is given by the formula .
Given: Radius () = Height () =
Step 1: Substitute the given values into the formula.
Step 2: Calculate the square of the radius.
Step 3: Multiply the numerical values. Answer: \frac{200{3} \pi cm^3}
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Q9. Find the Volume of the triangular prism a) The volume of a prism is given by the formula V = A_base × L, where A_base is the area of the base and L is the length (or height) of the prism.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.