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Find the Volume of the triangular prism. a) a triangular prism with base 12cm, height 10cm, length 20cm. b) a triangular prism with base 8in, height 12in, length ??? . What is the Volume of a cone with a radius of 5cm and a height of 8cm?

Mathematics

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2 parts
a

1200 cm31200 \text{ cm}^3

b

384 in3384 \text{ in}^3

2003π cm3\frac{200}{3} \pi \text{ cm}^3

Step-by-step solution

7 steps

Q9. Find the Volume of the triangular prism

Part a· 2 steps

The volume of a prism is given by the formula V=Abase×LV = A_{base} \times L, where AbaseA_{base} is the area of the base and LL is the length (or height) of the prism. For a triangular prism, the base is a triangle, and its area is Atriangle=12×base×heightA_{triangle} = \frac{1}{2} \times base \times height.

Given:
Base of the triangle (bb) = 12 cm12 \text{ cm}
Height of the triangle (hth_t) = 10 cm10 \text{ cm}
Length of the prism (LL) = 20 cm20 \text{ cm}

  1. Calculate the area of the triangular base.

    Abase=12×b×htA_{base} = \frac{1}{2} \times b \times h_t Abase=12×12 cm×10 cmA_{base} = \frac{1}{2} \times 12 \text{ cm} \times 10 \text{ cm} Abase=60 cm2A_{base} = 60 \text{ cm}^2
  2. Calculate the volume of the triangular prism.

    V=Abase×LV = A_{base} \times L V=60 cm2×20 cmV = 60 \text{ cm}^2 \times 20 \text{ cm} V=1200 cm3V = 1200 \text{ cm}^3

    Answer: 1200 cm^3

Part b

384 in3384 \text{ in}^3

For question 9b, the problem asks for the volume of a triangular prism, but the accompanying diagram shows a rectangular prism. I will solve for a triangular prism, assuming the base of the triangle is 8 inches8 \text{ inches}, the height of the triangle is 8 inches8 \text{ inches} (derived from the square base shown in the diagram), and the length of the prism is 12 inches12 \text{ inches}.

Given (based on assumption for triangular prism):
Base of the triangle (bb) = 8 in8 \text{ in}
Height of the triangle (hth_t) = 8 in8 \text{ in}
Length of the prism (LL) = 12 in12 \text{ in}

  1. Calculate the area of the triangular base.

    Abase=12×b×htA_{base} = \frac{1}{2} \times b \times h_t Abase=12×8 in×8 inA_{base} = \frac{1}{2} \times 8 \text{ in} \times 8 \text{ in} Abase=32 in2A_{base} = 32 \text{ in}^2
  2. Calculate the volume of the triangular prism.

    V=Abase×LV = A_{base} \times L V=32 in2×12 inV = 32 \text{ in}^2 \times 12 \text{ in} V=384 in3V = 384 \text{ in}^3

    Answer: 384 in^3

    Q10. What is the Volume of a cone with a radius of 5 cm and a height of 8 cm?
    The volume of a cone is given by the formula V=13πr2hV = \frac{1}{3} \pi r^2 h.

    Given:
    Radius (rr) = 5 cm5 \text{ cm}
    Height (hh) = 8 cm8 \text{ cm}

  3. Substitute the given values into the formula.

    V=13π(5 cm)2(8 cm)V = \frac{1}{3} \pi (5 \text{ cm})^2 (8 \text{ cm})
  4. Calculate the square of the radius.

    V=13π(25 cm2)(8 cm)V = \frac{1}{3} \pi (25 \text{ cm}^2) (8 \text{ cm})
  5. Multiply the numerical values.

    V=2003π cm3V = \frac{200}{3} \pi \text{ cm}^3

    Answer: \frac{200}{3} \pi cm^3

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