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The daily sales of a shop is birr 2400. If the shop owner pays 4.5% sales tax, how much does he pay from his daily sales?

Mathematics

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Answer

D

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Part 9· 2 steps

A person crossed a 600 meters long street in 4 minutes. What was his speed per hour?

  1. Convert the distance to kilometers and time to hours.

    Distance = 600 meters = 6001000\frac{600}{1000} km = 0.6 km
    Time = 4 minutes = 460\frac{4}{60} hours = 115\frac{1}{15} hours

  2. Calculate the speed.

    Speed = DistanceTime\frac{\text{Distance}}{\text{Time}}

    Speed=0.6 km115 hr=0.6×15 km/hr\text{Speed} = \frac{0.6 \text{ km}}{\frac{1}{15} \text{ hr}} = 0.6 \times 15 \text{ km/hr} 0.6×15=9 km/hr0.6 \times 15 = 9 \text{ km/hr}

    The correct option is (D).

    Answer: D) 9 km/hr\boxed{\text{D) 9 km/hr}}

Part 10· 3 steps

In a company, a regular work time is 40 hours per week and the rate of payment for over time work is 1121\frac{1}{2} times the regular rate (per hour). How much is the payment for an employee who worked 52 hours in a week if his hourly regular payment rate is 30?

  1. Determine regular and overtime hours.

    Regular hours = 40 hours
    Total hours worked = 52 hours
    Overtime hours = Total hours worked - Regular hours

    52−40=12 hours52 - 40 = 12 \text{ hours}

  2. Calculate regular and overtime payment rates.

    Regular rate = 30 birr/hour
    Overtime rate = 112×Regular rate=1.5×30 birr/hour1\frac{1}{2} \times \text{Regular rate} = 1.5 \times 30 \text{ birr/hour}

    1.5×30=45 birr/hour1.5 \times 30 = 45 \text{ birr/hour}

  3. Calculate the total payment.

    Payment for regular hours = Regular hours ×\times Regular rate

    40×30=1200 birr40 \times 30 = 1200 \text{ birr}

    Payment for overtime hours = Overtime hours ×\times Overtime rate

    12×45=540 birr12 \times 45 = 540 \text{ birr}

    Total payment = Payment for regular hours + Payment for overtime hours

    1200+540=1740 birr1200 + 540 = 1740 \text{ birr}

    The correct option is (C).

    Answer: C) Birr 1740\boxed{\text{C) Birr 1740}}

Part 11· 3 steps

20 friends went to a movie theatre. The average cost of the movie ticket for 19 friends was 120 birr. But one of the friends paid 38 birr more than the average cost for all the 19 friends. What was the total amount paid by all of them together?

  1. Calculate the total cost for the 19 friends.

    Average cost for 19 friends = 120 birr
    Total cost for 19 friends = 19×120 birr19 \times 120 \text{ birr}

    19×120=2280 birr19 \times 120 = 2280 \text{ birr}

  2. Calculate the cost for the 20th friend.

    The 20th friend paid 38 birr more than the average cost for the 19 friends.
    Cost for the 20th friend = 120+38 birr120 + 38 \text{ birr}

    120+38=158 birr120 + 38 = 158 \text{ birr}

  3. Calculate the total amount paid by all 20 friends.

    Total amount = Total cost for 19 friends + Cost for the 20th friend

    2280+158=2438 birr2280 + 158 = 2438 \text{ birr}

    The correct option is (A).

    Answer: A) 2,438\boxed{\text{A) 2,438}}

Part 12· 3 steps

A retailer purchases shirts from a distributor at the rate of birr 300 per shirt and puts the label of birr 450 on each shirt. If the retailer allows some discount and still makes a profit of 23%, then what is the discount percentage offered by the shopkeeper?

  1. Calculate the selling price (SP) of the shirt.

    Cost Price (CP) = 300 birr
    Profit percentage = 23%
    Selling Price (SP) = CP ×(1+Profit percentage)\times (1 + \text{Profit percentage})

    SP=300×(1+0.23)=300×1.23\text{SP} = 300 \times (1 + 0.23) = 300 \times 1.23 300×1.23=369 birr300 \times 1.23 = 369 \text{ birr}

  2. Calculate the discount amount.

    Marked Price (MP) = 450 birr
    Discount = Marked Price - Selling Price

    450−369=81 birr450 - 369 = 81 \text{ birr}

  3. Calculate the discount percentage.

    Discount percentage = DiscountMarked Price×100%\frac{\text{Discount}}{\text{Marked Price}} \times 100\%

    81450×100%=0.18×100%=18%\frac{81}{450} \times 100\% = 0.18 \times 100\% = 18\%

    The correct option is (C).

    Answer: \boxed{\text{C) 18%}}

Part 13· 2 steps

The speeds of two trains are in the ratio 6:7. If the second train runs 364 km in 4 hours, then the speed of the first train is _____.

  1. Calculate the speed of the second train.

    Distance = 364 km
    Time = 4 hours
    Speed of second train = DistanceTime\frac{\text{Distance}}{\text{Time}}

    Speed of second train=364 km4 hr=91 km/hr\text{Speed of second train} = \frac{364 \text{ km}}{4 \text{ hr}} = 91 \text{ km/hr}

  2. Use the given ratio to find the speed of the first train.

    Let the speeds of the first and second trains be S1S_1 and S2S_2 respectively.
    The ratio S1:S2=6:7S_1 : S_2 = 6 : 7.
    So, S1S2=67\frac{S_1}{S_2} = \frac{6}{7}.
    We know S2=91 km/hrS_2 = 91 \text{ km/hr}.

    S191=67\frac{S_1}{91} = \frac{6}{7} S1=67×91S_1 = \frac{6}{7} \times 91 S1=6×13=78 km/hrS_1 = 6 \times 13 = 78 \text{ km/hr}

    The correct option is (C).

    Answer: C) 78 km/hr\boxed{\text{C) 78 km/hr}}

Part 14· 2 steps

Average of five numbers is 20. If each number is multiplied by 2, what will be the new average?

  1. Understand the property of averages.

    If each number in a set is multiplied by a constant, the new average of the set will be the original average multiplied by that same constant.

  2. Calculate the new average.

    Original average = 20
    Each number is multiplied by 2.
    New average = Original average ×\times 2

    20×2=4020 \times 2 = 40

    Alternatively:
    Sum of five numbers = Average ×\times Number of numbers = 20×5=10020 \times 5 = 100.
    If each number is multiplied by 2, the new sum will be 100×2=200100 \times 2 = 200.
    New average = New sumNumber of numbers=2005=40\frac{\text{New sum}}{\text{Number of numbers}} = \frac{200}{5} = 40.
    The correct option is (D).

    Answer: D) 40\boxed{\text{D) 40}}

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