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The data below reps the ages in months at which 6 most babies started walking: 9, 11, 12, 13, 11 and 10. Without using a calculator, find the exact value of the variance of the data.

Mathematics

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Answer

53\mathbf{\frac{5}{3}}

Step-by-step solution

4 steps

Haya Pretty, hapa kuna suluhisho la swali lako la takwimu:

Swali: Data iliyo hapa chini inawakilisha umri katika miezi ambapo watoto 6 walianza kutembea: $9, 11, 12, 13, 11$ na 10. Bila kutumia kikokotoo, pata thamani kamili ya variance ya data.

  1. Panga data na ukokotoe wastani (mean), xˉ\bar{x}.

    Data iliyopangwa: 9,10,11,11,12,139, 10, 11, 11, 12, 13.
    Jumla ya data, ∑x=9+10+11+11+12+13=66\sum x = 9 + 10 + 11 + 11 + 12 + 13 = 66.
    Idadi ya data, n=6n = 6.
    Wastani, xˉ=∑xn=666=11\bar{x} = \frac{\sum x}{n} = \frac{66}{6} = 11.

  2. Jaza jedwali kwa kukokotoa x−xˉx - \bar{x} na (x−xˉ)2(x - \bar{x})^2 kwa kila thamani ya xx.

    ages (xx)x−xˉx - \bar{x}(x−xˉ)2(x - \bar{x})^2
    99−11=−29 - 11 = -2(−2)2=4(-2)^2 = 4
    1010−11=−110 - 11 = -1(−1)2=1(-1)^2 = 1
    1111−11=011 - 11 = 0(0)2=0(0)^2 = 0
    1111−11=011 - 11 = 0(0)2=0(0)^2 = 0
    1212−11=112 - 11 = 1(1)2=1(1)^2 = 1
    1313−11=213 - 11 = 2(2)2=4(2)^2 = 4
  3. Kokotoa jumla ya (x−xˉ)2(x - \bar{x})^2.

    ∑(x−xˉ)2=4+1+0+0+1+4=10\sum (x - \bar{x})^2 = 4 + 1 + 0 + 0 + 1 + 4 = 10
  4. Kokotoa variance (σ2\sigma^2).

    Fomula ya variance ni σ2=∑(x−xˉ)2n\sigma^2 = \frac{\sum (x - \bar{x})^2}{n}.

    σ2=106\sigma^2 = \frac{10}{6} σ2=53\sigma^2 = \frac{5}{3}

    Thamani kamili ya variance ya data ni 53\boxed{\mathbf{\frac{5}{3}}}.

    Hiyo ni yote kwa leo! Umefanya vizuri sana.

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