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The table below shows the ages of a group of girls who were born in March. What is the mean age of the girls?

Mathematics

ScanSolve AI Answer

Answer

12.8

Step-by-step solution

5 steps
  1. State the formula for the mean age.

    The mean age xˉ\bar{x} (in years) is given by

    xˉ=∑(xi⋅fi)∑fi\bar{x} = \frac{\sum (x_i \cdot f_i)}{\sum f_i}

    where xix_i is the age in years and fif_i is the number of girls of that age.

  2. List the data from the table.

    Age (years)Number of girls113124132145151\begin{array}{c|c} \text{Age (years)} & \text{Number of girls} \\ \hline 11 & 3 \\ 12 & 4 \\ 13 & 2 \\ 14 & 5 \\ 15 & 1 \\ \end{array}
  3. Calculate the total number of girls, ∑fi\sum f_i.

    ∑fi=3+4+2+5+1\sum f_i = 3 + 4 + 2 + 5 + 1 =7+2=9= 7 + 2 = 9 9+5=149 + 5 = 14 14+1=1514 + 1 = 15

    Total number of girls =15= 15.

  4. Calculate the total age sum, ∑(xi⋅fi)\sum (x_i \cdot f_i) (in years).

    11×3=3311 \times 3 = 33 12×4=4812 \times 4 = 48 13×2=2613 \times 2 = 26 14×5=7014 \times 5 = 70 15×1=1515 \times 1 = 15 ∑(xi⋅fi)=33+48+26+70+15\sum (x_i \cdot f_i) = 33 + 48 + 26 + 70 + 15 33+48=8133 + 48 = 81 81+26=10781 + 26 = 107 107+70=177107 + 70 = 177 177+15=192177 + 15 = 192

    Total age sum =192= 192 years.

  5. Calculate the mean age.

    xˉ=19215\bar{x} = \frac{192}{15} 15×12=18015 \times 12 = 180 192−180=12192 - 180 = 12 1215=0.8\frac{12}{15} = 0.8

    xˉ=12+0.8=12.8\bar{x} = 12 + 0.8 = 12.8 years.

    The mean age of the girls is 12.8 years.
    12.8

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