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What are the definitions and properties of the following: identity function, explicit function, hyperbolic identities, hyperbolic cosecant, limits involving powers, the constant e, and function notati

Mathematics

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Here are the solutions to the multiple-choice questions:

1. The function f(x)=xf(x) = x is a linear function (its graph is a straight line), an identity function (it maps every element to itself), and an odd function (f(−x)=−x=−f(x)f(-x) = -x = -f(x)). Therefore, all the given options are correct.

  • D) All are correct

2. If yy is expressed directly in terms of xx as y=f(x)y = f(x), it means yy is explicitly defined by xx. This is called an explicit function.

  • A) An explicit function

3. The fundamental hyperbolic identity is analogous to the Pythagorean identity for trigonometric functions. It states that cosh⁡2x−sinh⁡2x=1\cosh^2 x - \sinh^2 x = 1.

  • C) 1

4. The hyperbolic cosecant function, cosech x\text{cosech } x, is the reciprocal of the hyperbolic sine function, sinh⁡x\sinh x.
We know that sinh⁡x=ex−e−x2\sinh x = \frac{e^x - e^{-x}}{2}.
Therefore,

cosech x=1sinh⁡x=1ex−e−x2=2ex−e−x\text{cosech } x = \frac{1}{\sinh x} = \frac{1}{\frac{e^x - e^{-x}}{2}} = \frac{2}{e^x - e^{-x}}
  • C) 2ex−e−x\frac{2}{e^x - e^{-x}}

5. This is a standard limit form lim⁡x→axn−anx−a=nan−1\lim_{x \to a} \frac{x^n - a^n}{x - a} = n a^{n-1}.
For the given limit, n=3n=3.

lim⁡x→ax3−a3x−a=3a3−1=3a2\lim_{x \to a} \frac{x^3 - a^3}{x - a} = 3a^{3-1} = 3a^2
  • B) 3a23a^2

6. This is the definition of the mathematical constant ee.

lim⁡x→0(1+x)1/x=e\lim_{x \to 0} (1 + x)^{1/x} = e
  • B) E

7. The notation y=f(x)y = f(x) was introduced by Leonhard Euler in the 18th century.

  • B) Euler

8. To find f(0)f(0), substitute x=0x=0 into the function f(x)=x2−2x+1f(x) = x^2 - 2x + 1.

f(0)=(0)2−2(0)+1=0−0+1=1f(0) = (0)^2 - 2(0) + 1 = 0 - 0 + 1 = 1
  • C) 1

9. When we define a function ff from set XX to set YY, the set XX containing all possible input values is called the domain of ff.

  • A) Domain of f

10. The identity function is f(x)=xf(x) = x. Its graph is a straight line that passes through the origin (0,0)(0,0) and makes a 45∘45^\circ angle with the positive x-axis, thereby bisecting the first and third quadrants.

  • A) Bisecting the 1st1^\text{st} and 3rd3^\text{rd} quad

11. If f(x)=x2f(x) = x^2, the output values (range) are always non-negative, because the square of any real number is greater than or equal to zero.
The range is [0,∞[[0, \infty[.

  • A) [0,∞[[0, \infty[

12. For the function f(x)=xx2−4f(x) = \frac{x}{x^2 - 4}, the denominator cannot be zero.

x2−4≠0x^2 - 4 \ne 0 x2≠4x^2 \ne 4 x≠±2x \ne \pm 2

Therefore, the domain consists of all real numbers except −2-2 and 2.

  • C) All real numbers except -2, 2

13. For a graph to represent a function, it must pass the vertical line test. This means that any vertical line drawn through the graph must intersect it at exactly one point. If it intersects at more than one point, it means there are multiple yy-values for a single xx-value, which is not allowed for a function.

  • A) One point only

14. The function is defined in two parts:

  1. f(x)=xf(x) = x for 0≤x≤10 \le x \le 1. This interval is [0,1][0, 1].
  2. f(x)=x−1f(x) = x-1 for 1<x<21 < x < 2. This interval is (1,2)(1, 2). The domain of ff is the union of these two intervals: [0,1]∪(1,2)=[0,2)[0, 1] \cup (1, 2) = [0, 2). Among the given options, (0,2)(0,2) is the closest, although it incorrectly excludes x=0x=0. Given the options, it is the most likely intended answer.
  • A) (0,2)(0,2)

15. A linear function is defined by an equation of the form y=mx+cy = mx + c, where mm and cc are constants. The graph of any such equation is always a straight line.

  • A) Straight line

16. The identity function f:X→Xf: X \to X maps every element of set XX to itself. Therefore, its domain is XX (the set of all possible inputs) and its range is also XX (the set of all possible outputs).

  • A) X

17. A linear function f(x)=ax+bf(x) = ax + b is a constant function if its value does not change with xx. This occurs when the coefficient of xx is zero.
If a=0a=0, then f(x)=0⋅x+b=bf(x) = 0 \cdot x + b = b, which is a constant value.

  • D) a=0a=0
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