What is the derivative of x³ + 2x with respect to x? Give a full worked solution with steps.

Mathematics

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Answer

The derivative of x3+2xx^3 + 2x with respect to xx is 3x2+23x^2 + 2.

Step-by-step solution

4 steps

Full Worked Solution:

To find the derivative of f(x)=x3+2xf(x) = x^3 + 2x, we will use the following differentiation rules:

  1. Sum Rule: ddx[g(x)+h(x)]=ddx[g(x)]+ddx[h(x)]\frac{d}{dx}[g(x) + h(x)] = \frac{d}{dx}[g(x)] + \frac{d}{dx}[h(x)]
  2. Power Rule: ddx[xn]=nxn−1\frac{d}{dx}[x^n] = nx^{n-1}
  3. Constant Multiple Rule: ddx[cf(x)]=cddx[f(x)]\frac{d}{dx}[cf(x)] = c\frac{d}{dx}[f(x)]

Let f(x)=x3+2xf(x) = x^3 + 2x.

  1. Apply the Sum Rule

    We can differentiate each term separately:
    ddx(x3+2x)=ddx(x3)+ddx(2x)\frac{d}{dx}(x^3 + 2x) = \frac{d}{dx}(x^3) + \frac{d}{dx}(2x)

  2. Differentiate the first term, x3x^3

    Using the Power Rule where n=3n=3:
    ddx(x3)=3x3−1=3x2\frac{d}{dx}(x^3) = 3x^{3-1} = 3x^2

  3. Differentiate the second term, $2x$

    Using the Constant Multiple Rule and the Power Rule (where x=x1x = x^1, so n=1n=1):
    ddx(2x)=2⋅ddx(x1)\frac{d}{dx}(2x) = 2 \cdot \frac{d}{dx}(x^1)
    ddx(x1)=1x1−1=1x0=1⋅1=1\frac{d}{dx}(x^1) = 1x^{1-1} = 1x^0 = 1 \cdot 1 = 1
    So, ddx(2x)=2⋅1=2\frac{d}{dx}(2x) = 2 \cdot 1 = 2

  4. Combine the results

    Substitute the derivatives of each term back into the expression from Step 1:
    ddx(x3+2x)=3x2+2\frac{d}{dx}(x^3 + 2x) = 3x^2 + 2

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