The diagram shows a shape ABCD which is composed of a rectangle and a sector of a circle. The perimeter of the shape is 125.92 m. A pool is in the shape of a circle with diameter 4.73 m. The cost of f

Distance AD = 10.9 m
Distance CB = 9.43 m

Ratio = $10.9 : 9.43$

Ratio = $1090 : 943$

$943 = 23 \times 41$
$1090 = 2 \times 5 \times 109$
There are no common factors between 1090 and 943.

The simplified ratio is $\boxed{\text{1090 : 943}}$.

4.1.2

Perimeter of ABCD = 125.92 m
Distance AD = 10.9 m
Distance CB = 9.43 m
Curved distance AB = 57.5 m

Perimeter = AD + CD + CB + Curved AB
$125.92 = 10.9 + \text{CD} + 9.43 + 57.5$

$10.9 + 9.43 + 57.5 = 77.83$ m

$125.92 = \text{CD} + 77.83$
$\text{CD} = 125.92 - 77.83$
$\text{CD} = 48.09$ m

The distance CD is $\boxed{\text{48.09 m}}$.

4.1.3

Diameter = 4.73 m

Radius = $\frac{4.73}{2}$
Radius = 2.365 m

The length of the radius of the pool is $\boxed{\text{2.365 m}}$.

4.1.4

Length of curved side AB = 57.5 m
Cost per running metre = R$97.56$

Total cost = Length of AB $\times$ Cost per running metre
Total cost = $57.5 \text{ m} \times \text{R}97.56/\text{m}$
Total cost = R$5614.70$

The total cost of erecting the fence is $\boxed{\text{R5614.70}}$.

4.2.1

8.4 litres of petrol allows travel of 80 km.

Distance per litre = $\frac{80 \text{ km}}{8.4 \text{ L}}$

Total distance = $\frac{80 \text{ km}}{8.4 \text{ L}} \times 60 \text{ L}$
Total distance = $\frac{4800}{8.4}$ km
Total distance $\approx 571.42857$ km

Total distance $\approx 571$ km

The vehicle can travel approximately $\boxed{\text{571 km}}$.

4.2.2

Distance = 196 km
Time = 1 hour 45 minutes

45 minutes = $\frac{45}{60}$ hours = 0.75 hours
Total time = $1 + 0.75 = 1.75$ hours

Average Speed = $\frac{\text{distance}}{\text{time}}$
Average Speed = $\frac{196 \text{ km}}{1.75 \text{ hours}}$
Average Speed = 112 km/h

The average speed of the vehicle is $\boxed{\text{112 km/h}}$.