The equation of a circle is x2 + y2 − 4x + 6y + 4 = 0. On the grid provided below, draw the circle.

Take half of the coefficient of $x$ (which is $-4$), square it ($(-2)^2 = 4$), and add it to both sides.

$$(x^2 - 4x + 4) + (y^2 + 6y) = -4 + 4$$

Take half of the coefficient of $y$ (which is 6), square it ($(3)^2 = 9$), and add it to both sides.

$$(x^2 - 4x + 4) + (y^2 + 6y + 9) = -4 + 4 + 9$$

Comparing this to the standard form $(x-h)^2 + (y-k)^2 = r^2$:
The center $(h,k)$ is $(2, -3)$.
The radius squared $r^2$ is 9, so the radius $r = \sqrt{9} = 3$.

To draw the circle on a grid, you would:

1. Locate the center point at $(2, -3)$.
2. From the center, measure out 3 units in all directions (up, down, left, right) to mark points on the circle.
3. Draw a smooth curve connecting these points to form the circle.

The center of the circle is $\boxed{(2, -3)}$ and the radius is $\boxed{3}$.