The first ter of an Ap is equal to twice the common difference d.find in terms of d,the 5th term of the A.p

The formula for the nth term of an Arithmetic Progression (AP) is given by:
$a_n = a_1 + (n-1)d$
where $a_n$ is the nth term, $a_1$ is the first term, and $d$ is the common difference.

We are given that the first term ($a_1$) is equal to twice the common difference ($d$):
$a_1 = 2d$

Substitute $n=5$ into the formula for the nth term:
$a_5 = a_1 + (5-1)d$
$a_5 = a_1 + 4d$

Substitute $a_1 = 2d$ into the equation for $a_5$:
$a_5 = (2d) + 4d$
$a_5 = 6d$

The 5th term of the AP in terms of $d$ is:
$6d$