In an A.P., the first term is a and the common difference is d. Express a in terms of d given that A14 = 5A2.

a) Find a simplified equation of $a$ in terms of $d$.

Step 1: Express the terms of the A.P.
Let the first term of the A.P. be $A_1 = a$ and the common difference be $d$.
The $n$-th term of an A.P. is given by $A_n = A_1 + (n-1)d$.
The 2nd term of the A.P. is $A_2 = a + (2-1)d = a+d$.
The 14th term of the A.P. is $A_{14} = a + (14-1)d = a+13d$.
The 92