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The following diagram shows the frustum of a cone. The top and bottom diameters are 6 cm and 18 cm respectively. Given that its perpendicular height is 15 cm, calculate the volume of the frustum.

Mathematics

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Answer

1225.38 cm3\text{1225.38 cm}^3

Step-by-step solution

5 steps

The first question is too blurry to read completely. Please send a clearer image if you'd like me to solve it.

For question 11, we need to calculate the volume of the frustum.

  1. Identify the given dimensions and calculate the radii.

    The height of the frustum is h=10h = 10 cm.
    The top diameter is 6 cm, so the top radius is r1=62=3r_1 = \frac{6}{2} = 3 cm.
    The bottom diameter is 18 cm, so the bottom radius is r2=182=9r_2 = \frac{18}{2} = 9 cm.
    We are given π=3.142\pi = 3.142.

  2. Write down the formula for the volume of a frustum.

    The volume VV of a frustum is given by the formula:

    V=13πh(r12+r1r2+r22)V = \frac{1}{3} \pi h (r_1^2 + r_1 r_2 + r_2^2)
  3. Substitute the values into the formula.

    V=13×3.142×10×(32+(3)(9)+92)V = \frac{1}{3} \times 3.142 \times 10 \times (3^2 + (3)(9) + 9^2)
  4. Calculate the terms inside the parenthesis.

    V=13×3.142×10×(9+27+81)V = \frac{1}{3} \times 3.142 \times 10 \times (9 + 27 + 81) V=13×3.142×10×(117)V = \frac{1}{3} \times 3.142 \times 10 \times (117)
  5. Perform the multiplication to find the volume.

    V=3.142×10×1173V = 3.142 \times 10 \times \frac{117}{3} V=3.142×10×39V = 3.142 \times 10 \times 39 V=31.42×39V = 31.42 \times 39 V=1225.38 cm3V = 1225.38 \text{ cm}^3

    The volume of the frustum is 1225.38 cm3\text{1225.38 cm}^3.

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