This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Step 3: Calculate the variance (s^2). The formula for variance is: s^2 = ( fx^2)/(N) - (( fx)/(N))^2 Substitute the given values: s^2 = (10468.9)/(80) - ((909)/(80))^2 Perform the division: s^2 = 130.86125 - (11.3625)^2 Calculate the square: s^2 = 130.86125 - 129.00640625 Subtract the values: s^2 = 1.85484375 (g/100ml)^2 Rounding to two decimal places: The variance is 1.85 (g/100ml)^2. Step 4: Calculate the range. The range is estimated as the difference between the upper class boundary of the highest class and the lower class boundary of the lowest class. Upper class boundary of 14.0-14.9: 14.9 + 0.05 = 14.95 Lower class boundary of 8.0-8.9: 8.0 - 0.05 = 7.95 Calculate the range: Range = 14.95 - 7.95 = 7.0 g/100ml The range is 7.0 g/100ml. b) Step 1: Identify the classes with haemoglobin levels less than 11.0 g/100ml. The classes with haemoglobin levels less than 11.0 g/100ml are: • 8.0-8.9 • 9.0-9.9 • 10.0-10.9