To solve the inequality, we will first find a common denominator for all terms and then clear the fractions.
The given inequality is:
−1+3p2≤41−6p5
We are given that p>0.
Step 1: Find the least common multiple (LCM) of the denominators 1,3p,4, and 6p.
The LCM of 1,3p,4,6p is 12p.
Step 2: Multiply every term in the inequality by the LCM, 12p. Since p>0, 12p is positive, so the inequality sign will not change direction.
12p(−1)+12p(3p2)≤12p(41)−12p(6p5)
Step 3: Simplify each term.
−12p+3p24p≤412p−6p60p
−12p+8≤3p−10
Step 4: Gather terms with p on one side and constant terms on the other side.
Add 12p to both sides:
8≤3p+12p−10
8≤15p−10
Add 10 to both sides:
8+10≤15p
18≤15p
Step 5: Solve for p.
Divide both sides by 15:
1518≤p
Step 6: Simplify the fraction.
56≤p
This can also be written as p≥56.
Since 56=1.2, and 1.2>0, the condition p>0 is satisfied.
The solution for p is:
p \ge \frac{6{5}}