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The given inequality is:

Mathematics

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Answer

p≥65p \ge \frac{6}{5}

Step-by-step solution

6 steps

To solve the inequality, we will first find a common denominator for all terms and then clear the fractions.

The given inequality is:

−1+23p≤14−56p-1 + \frac{2}{3p} \le \frac{1}{4} - \frac{5}{6p}

We are given that p>0p > 0.

  1. Find the least common multiple (LCM) of the denominators $1, 3p, 4,$ and $6p$.

    The LCM of $1, 3p, 4, 6p$ is $12p$.

  2. Multiply every term in the inequality by the LCM, $12p$.

    Since p>0p > 0, 12p12p is positive, so the inequality sign will not change direction.

    12p(−1)+12p(23p)≤12p(14)−12p(56p)12p(-1) + 12p\left(\frac{2}{3p}\right) \le 12p\left(\frac{1}{4}\right) - 12p\left(\frac{5}{6p}\right)
  3. Simplify each term.

    −12p+24p3p≤12p4−60p6p-12p + \frac{24p}{3p} \le \frac{12p}{4} - \frac{60p}{6p} −12p+8≤3p−10-12p + 8 \le 3p - 10
  4. Gather terms with pp on one side and constant terms on the other side.

    Add 12p12p to both sides:

    8≤3p+12p−108 \le 3p + 12p - 10 8≤15p−108 \le 15p - 10

    Add 10 to both sides:

    8+10≤15p8 + 10 \le 15p 18≤15p18 \le 15p
  5. Solve for pp.

    Divide both sides by 15:

    1815≤p\frac{18}{15} \le p
  6. Simplify the fraction.

    65≤p\frac{6}{5} \le p

    This can also be written as p≥65p \ge \frac{6}{5}.
    Since 65=1.2\frac{6}{5} = 1.2, and 1.2>01.2 > 0, the condition p>0p > 0 is satisfied.

    The solution for pp is:

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