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The given matrix is:

Mathematics

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5 steps

The given matrix is:

[1030542225103752]\begin{bmatrix} 1 & 0 & 3 & 0 \\ 5 & 4 & 2 & 2 \\ 2 & 5 & 1 & 0 \\ 3 & 7 & 5 & 2 \end{bmatrix}
  1. Make the entries below the leading 1 in the first column zero.

    Perform the following row operations:
    R2←R2−5R1R_2 \leftarrow R_2 - 5R_1
    R3←R3−2R1R_3 \leftarrow R_3 - 2R_1
    R4←R4−3R1R_4 \leftarrow R_4 - 3R_1

    The matrix becomes:

    [103004−13205−5007−42]\begin{bmatrix} 1 & 0 & 3 & 0 \\ 0 & 4 & -13 & 2 \\ 0 & 5 & -5 & 0 \\ 0 & 7 & -4 & 2 \end{bmatrix}
  2. Make the leading entry in the second row a 1.

    Perform the row operation:
    R2←14R2R_2 \leftarrow \frac{1}{4}R_2

    The matrix becomes:

    [103001−1341205−5007−42]\begin{bmatrix} 1 & 0 & 3 & 0 \\ 0 & 1 & -\frac{13}{4} & \frac{1}{2} \\ 0 & 5 & -5 & 0 \\ 0 & 7 & -4 & 2 \end{bmatrix}
  3. Make the entries below the leading 1 in the second column zero.

    Perform the following row operations:
    R3←R3−5R2R_3 \leftarrow R_3 - 5R_2
    R4←R4−7R2R_4 \leftarrow R_4 - 7R_2

    The matrix becomes:

    [103001−1341200454−5200754−32]\begin{bmatrix} 1 & 0 & 3 & 0 \\ 0 & 1 & -\frac{13}{4} & \frac{1}{2} \\ 0 & 0 & \frac{45}{4} & -\frac{5}{2} \\ 0 & 0 & \frac{75}{4} & -\frac{3}{2} \end{bmatrix}
  4. Make the leading entry in the third row a 1.

    Perform the row operation:
    R3←445R3R_3 \leftarrow \frac{4}{45}R_3

    The matrix becomes:

    [103001−13412001−2900754−32]\begin{bmatrix} 1 & 0 & 3 & 0 \\ 0 & 1 & -\frac{13}{4} & \frac{1}{2} \\ 0 & 0 & 1 & -\frac{2}{9} \\ 0 & 0 & \frac{75}{4} & -\frac{3}{2} \end{bmatrix}
  5. Make the entry below the leading 1 in the third column zero.

    Perform the row operation:
    R4←R4−754R3R_4 \leftarrow R_4 - \frac{75}{4}R_3

    The matrix becomes:

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