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The height of 100 maize plants were measured to the nearest centimeter and the results recorded in the table below. (a) complete the table. (b) Calculate 2 d.p. (i) The mean (ii) The standard deviation. (c) Using the above plot an ogive and use it to find the 30th percentile.

Mathematics

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Answers

3 parts
b(i)

42.15\text{42.15}

b(ii)

7.66\text{7.66}

c

38.11\text{38.11}

Step-by-step solution

10 steps

Huu hapa ni utatuzi wa swali lako:

Part a

Kamilisha jedwali

Kwanza, tunabainisha kuwa thamani ya dd inatokana na fomula d=x−Acd = \frac{x - A}{c}, ambapo AA ni wastani uliochukuliwa (assumed mean) na cc ni upana wa darasa (class width). Kutoka jedwali, d=0d=0 wakati x=42x=42, hivyo A=42A=42. Upana wa darasa c=30−25=5c = 30-25 = 5.

Sasa, hebu tukamilishe safu za fdfd na fd2fd^2:

HeightFrequency (f)xdd²fdfd²CF
25-29527-395×−3=−155 \times -3 = -155×9=455 \times 9 = 455
30-341232-2412×−2=−2412 \times -2 = -2412×4=4812 \times 4 = 4817
35-391837-1118×−1=−1818 \times -1 = -1818×1=1818 \times 1 = 1835
40-4430420030×0=030 \times 0 = 030×0=030 \times 0 = 065
45-4917471117×1=1717 \times 1 = 1717×1=1717 \times 1 = 1782
50-5411522411×2=2211 \times 2 = 2211×4=4411 \times 4 = 4493
55-59757397×3=217 \times 3 = 217×9=637 \times 9 = 63100
Jumla∑f=100\sum f = 100∑fd=3\sum fd = 3∑fd2=235\sum fd^2 = 235

Part b(i)

42.15\text{42.15}

Wastani (Mean)

Kokotoa

  1. Tumia fomula ya wastani kwa kutumia wastani uliochukuliwa.

    Fomula ni xˉ=A+∑fd∑f×c\bar{x} = A + \frac{\sum fd}{\sum f} \times c.
    Kutoka jedwali, A=42A = 42, ∑fd=3\sum fd = 3, ∑f=100\sum f = 100, na c=5c = 5.

  2. Badilisha thamani kwenye fomula na kokotoa.

    xˉ=42+3100×5\bar{x} = 42 + \frac{3}{100} \times 5 xˉ=42+15100\bar{x} = 42 + \frac{15}{100} xˉ=42+0.15\bar{x} = 42 + 0.15 xˉ=42.15\bar{x} = \boxed{\text{42.15}}

Part b(ii)

7.66\text{7.66}

Mkengeuko Wastani (Standard Deviation)

  1. Tumia fomula ya mkengeuko wastani kwa kutumia wastani uliochukuliwa.

    Fomula ni s=c∑fd2∑f−(∑fd∑f)2s = c \sqrt{\frac{\sum fd^2}{\sum f} - \left(\frac{\sum fd}{\sum f}\right)^2}.
    Kutoka jedwali, c=5c = 5, ∑fd2=235\sum fd^2 = 235, ∑fd=3\sum fd = 3, na ∑f=100\sum f = 100.

  2. Badilisha thamani kwenye fomula.

    s=5235100−(3100)2s = 5 \sqrt{\frac{235}{100} - \left(\frac{3}{100}\right)^2}
  3. Kokotoa ndani ya mizizi.

    s=52.35−(0.03)2s = 5 \sqrt{2.35 - (0.03)^2} s=52.35−0.0009s = 5 \sqrt{2.35 - 0.0009} s=52.3491s = 5 \sqrt{2.3491}
  4. Kokotoa mizizi ya mraba na zidisha.

    s≈5×1.532677s \approx 5 \times 1.532677 s≈7.663385s \approx 7.663385
  5. Zungusha jibu kwa sehemu mbili za desimali.

    s≈7.66s \approx \boxed{\text{7.66}}

Part c

38.11\text{38.11}

Chora ogive na utumie kupata asilimia ya 30 (30th percentile)

Ili kuchora ogive (cumulative frequency curve), utahitaji kupanga masafa ya juu ya darasa (upper class boundaries) dhidi ya masafa jumla (cumulative frequencies).

  1. Masafa ya Juu ya Darasa na Masafa Jumla

    • 25-29: 29.5, CF = 5
    • 30-34: 34.5, CF = 17
    • 35-39: 39.5, CF = 35
    • 40-44: 44.5, CF = 65
    • 45-49: 49.5, CF = 82
    • 50-54: 54.5, CF = 93
    • 55-59: 59.5, CF = 100 Anza ogive kwa (24.5, 0).
  2. Kuchora Ogive

    • Chora grafu ambapo mhimili wa x unawakilisha urefu (Height) na mhimili wa y unawakilisha masafa jumla (Cumulative Frequency).
    • Panga pointi zilizoorodheshwa hapo juu na uziunganishe kwa mstari laini.
  3. Kupata Asilimia ya 30 (30th Percentile)

    • Jumla ya masafa ni N=100N = 100.
    • Asilimia ya 30 inalingana na nafasi ya 0.30×N=0.30×100=300.30 \times N = 0.30 \times 100 = 30.
    • Kwenye ogive, tafuta 30 kwenye mhimili wa y (Cumulative Frequency).
    • Chora mstari mlalo kutoka CF=30CF=30 hadi uingiliane na ogive.
    • Kutoka sehemu ya makutano, chora mstari wima chini hadi mhimili wa x (Height).
    • Thamani kwenye mhimili wa x ambapo mstari wima unakatiza ndiyo asilimia ya 30.

    Kwa kutumia fomula ya kukokotoa asilimia (interpolation) kwa darasa la 35-39 (ambapo CF inatoka 17 hadi 35):

    P30=L+(30100N−CFbfp)×cP_{30} = L + \left(\frac{\frac{30}{100}N - CF_b}{f_p}\right) \times c

    Ambapo L=34.5L = 34.5 (mpaka wa chini wa darasa), N=100N = 100, CFb=17CF_b = 17 (CF kabla ya darasa), fp=18f_p = 18 (masafa ya darasa), c=5c = 5 (upana wa darasa).

    P30=34.5+(30−1718)×5P_{30} = 34.5 + \left(\frac{30 - 17}{18}\right) \times 5 P30=34.5+(1318)×5P_{30} = 34.5 + \left(\frac{13}{18}\right) \times 5 P30=34.5+6518P_{30} = 34.5 + \frac{65}{18} P30=34.5+3.6111...P_{30} = 34.5 + 3.6111... P30≈38.11P_{30} \approx \boxed{\text{38.11}}
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