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The image contains mathematical calculations related to circle equations and a table for statistical data analysis, with a note 'Complete table 6 Marks'. The main question appears to be related to completing the table.

Mathematics

ScanSolve AI Answer

Answer

(2, 3)
2
10.35

Step-by-step solution

6 steps

Here's a breakdown of the problems and the completed table.

: Circle Equation

The general equation of a circle is given by x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0.
The center of the circle is (−g,−f)(-g, -f) and the radius is r=g2+f2−cr = \sqrt{g^2 + f^2 - c}.

The given equation is x2+y2−4x−6y+9=0x^2 + y^2 - 4x - 6y + 9 = 0.

  1. Identify the coefficients.

    Comparing the given equation with the general form:

    2gx=−4x  ⟹  2g=−4  ⟹  g=−22gx = -4x \implies 2g = -4 \implies g = -2 2fy=−6y  ⟹  2f=−6  ⟹  f=−32fy = -6y \implies 2f = -6 \implies f = -3 c=9c = 9
  2. Calculate the center of the circle.

    The center is (−g,−f)(-g, -f).

    Center=(−(−2),−(−3))=(2,3)\text{Center} = (-(-2), -(-3)) = (2, 3)
  3. Calculate the radius of the circle.

    The radius is r=g2+f2−cr = \sqrt{g^2 + f^2 - c}.

    r=(−2)2+(−3)2−9r = \sqrt{(-2)^2 + (-3)^2 - 9} r=4+9−9r = \sqrt{4 + 9 - 9} r=4r = \sqrt{4} r=2r = 2

    The student's work for the circle equation is correct.
    The center of the circle is (2,3)\boxed{(2, 3)} and the radius is 2\boxed{2}.


    : Complete Table for Assumed Mean

    To complete the table and calculate the mean using the assumed mean method, we need to:

    1. Choose an assumed mean (AA). We will choose A=13A=13 (the midpoint of the class with the highest frequency).
    2. Determine the class width (cc). The class intervals are not perfectly uniform (0-5 has width 6, 6-10 has width 5, 11-15 has width 5). We will use the most common class width, c=5c=5, for the calculation of uu.
    3. Calculate the deviation d=x−Ad = x - A.
    4. Calculate u=x−Acu = \frac{x - A}{c}.
    5. Calculate u2u^2.
    6. Calculate FuFu and Fu2Fu^2.
    7. Sum the columns ∑F\sum F, ∑Fu\sum Fu, and ∑Fu2\sum Fu^2.
    8. Calculate the mean using the formula xˉ=A+∑Fu∑F×c\bar{x} = A + \frac{\sum Fu}{\sum F} \times c.

    Here is the completed table:

    MarksFxd = x - Au = (x - A)/cu^2FuFu^2C.B
    0-522.52.5−13=−10.52.5 - 13 = -10.5−10.55=−2.1\frac{-10.5}{5} = -2.1(−2.1)2=4.41(-2.1)^2 = 4.412×(−2.1)=−4.22 \times (-2.1) = -4.22×4.41=8.822 \times 4.41 = 8.82-0.5 - 5.5
    6-10888−13=−58 - 13 = -5−55=−1\frac{-5}{5} = -1(−1)2=1(-1)^2 = 18×(−1)=−88 \times (-1) = -88×1=88 \times 1 = 85.5 - 10.5
    11-15131313−13=013 - 13 = 005=0\frac{0}{5} = 002=00^2 = 013×0=013 \times 0 = 013×0=013 \times 0 = 010.5 - 15.5
    Total23-12.216.82
  4. Calculate the sum of frequencies.

    ∑F=2+8+13=23\sum F = 2 + 8 + 13 = 23
  5. Calculate the sum of FuFu.

    ∑Fu=−4.2−8+0=−12.2\sum Fu = -4.2 - 8 + 0 = -12.2
  6. Calculate the mean using the assumed mean formula.

    xˉ=A+∑Fu∑F×c\bar{x} = A + \frac{\sum Fu}{\sum F} \times c

    Substitute A=13A=13, ∑Fu=−12.2\sum Fu = -12.2, ∑F=23\sum F = 23, and c=5c=5:

    xˉ=13+−12.223×5\bar{x} = 13 + \frac{-12.2}{23} \times 5 xˉ=13+−6123\bar{x} = 13 + \frac{-61}{23} xˉ=13−2.65217...\bar{x} = 13 - 2.65217... xˉ≈10.35\bar{x} \approx 10.35

    The completed table is shown above, and the mean is 10.35\boxed{10.35}.

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