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The image shows a pyramid of boxes. The value in each box is the sum of the two boxes directly above it. Fill in the empty boxes.

Mathematics

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Step-by-step solution

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This problem presents a series of pyramid-style calculations where the value in a box is the sum of the two boxes directly above it. We will fill in the empty boxes based on this pattern.

  1. Calculate the value for the first empty box, located below 74kg and 42kg.

    This box is the sum of the two boxes above it.

    74 kg+42 kg=116 kg74 \text{ kg} + 42 \text{ kg} = 116 \text{ kg}

    The first empty box is 116 kg\boxed{\text{116 kg}}.

  2. Calculate the value for the second empty box, located to the right of 39kg.

    Let this empty box be XX. The box below 39kg and XX is 59kg.
    So, we set up the equation:

    39 kg+X=59 kg39 \text{ kg} + X = 59 \text{ kg}

    To find XX, subtract 39kg from 59kg:

    X=59 kg−39 kgX = 59 \text{ kg} - 39 \text{ kg} X=20 kgX = 20 \text{ kg}

    The empty box to the right of 39kg is 20 kg\boxed{\text{20 kg}}.

  3. Calculate the value for the third empty box, located below 45kg and 25kg.

    This box is the sum of the two boxes above it.

    45 kg+25 kg=70 kg45 \text{ kg} + 25 \text{ kg} = 70 \text{ kg}

    The empty box below 45kg and 25kg is 70 kg\boxed{\text{70 kg}}.

    The last two empty boxes (one to the right of the bottom-most 25kg, and the one below them) cannot be determined with the information provided in the image, as there are no additional values given to complete those calculations.

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