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The number of subsets of the first set is 30 more than the second. Find the number of elements in each set.

Mathematics

ScanSolve AI Answer

Answer

M=5,N=1M=5, N=1

Step-by-step solution

5 steps
  1. Define the number of subsets for each set.

    Let the first set have MM elements. The number of subsets for the first set is 2M2^M.
    Let the second set have NN elements. The number of subsets for the second set is 2N2^N.

  2. Set up the equation based on the problem statement.

    The number of subsets of the first set is 30 more than the second:

    2M=2N+302^M = 2^N + 30
  3. Rearrange the equation.

    2M−2N=302^M - 2^N = 30

    Factor out 2N2^N:

    2N(2M−N−1)=302^N (2^{M-N} - 1) = 30
  4. Find integer solutions for NN and MM.

    We need to find factors of 30 that are powers of 2. The factors of 30 are 1, 2, 3, 5, 6, 10, 15, 30.
    The only power of 2 that is a factor of 30 is 21=22^1 = 2.
    So, we must have 2N=22^N = 2.
    Therefore, N=1N=1.

  5. Substitute N=1N=1 back into the equation.

    21(2M−1−1)=302^1 (2^{M-1} - 1) = 30 2(2M−1−1)=302 (2^{M-1} - 1) = 30

    Divide both sides by 2:

    2M−1−1=152^{M-1} - 1 = 15

    Add 1 to both sides:

    2M−1=162^{M-1} = 16

    Express 16 as a power of 2:

    2M−1=242^{M-1} = 2^4

    Equate the exponents:

    M−1=4M-1 = 4 M=4+1M = 4 + 1 M=5M = 5

    The values are M=5M=5 and N=1N=1.

    The final answer is M=5,N=1M=5, N=1.

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