The outer measure of the wooden box is 2 m into 1.8 m into 0.5 m if the inner measure is the empty box is1.9 meter meter into 1.7 m into 0.4 m into 1.4meter, then find the Volume of wood used in the box

The outer dimensions are given as 2 m, 1.8 m, and 0.5 m.

$$V_{\text{outer}} = \text{Length}_{\text{outer}} \times \text{Width}_{\text{outer}} \times \text{Height}_{\text{outer}}$$ $$V_{\text{outer}} = 2\ \text{m} \times 1.8\ \text{m} \times 0.5\ \text{m}$$ $$V_{\text{outer}} = 1.8\ \text{m}^3$$

The inner dimensions are given as 1.9 m, 1.7 m, and 0.4 m (ignoring the extraneous "1.4meter" from the input).

$$V_{\text{inner}} = \text{Length}_{\text{inner}} \times \text{Width}_{\text{inner}} \times \text{Height}_{\text{inner}}$$ $$V_{\text{inner}} = 1.9\ \text{m} \times 1.7\ \text{m} \times 0.4\ \text{m}$$ $$V_{\text{inner}} = 3.23\ \text{m}^2 \times 0.4\ \text{m}$$ $$V_{\text{inner}} = 1.292\ \text{m}^3$$

The volume of wood used is the difference between the outer volume and the inner volume.

$$V_{\text{wood}} = V_{\text{outer}} - V_{\text{inner}}$$ $$V_{\text{wood}} = 1.8\ \text{m}^3 - 1.292\ \text{m}^3$$ $$V_{\text{wood}} = 0.508\ \text{m}^3$$

The volume of wood used in the box is $0.508\ \text{m}^3$.