Which box requires the lesser amount of material to make? Box (a) has length 60 cm, breadth 40 cm, and height 50 cm. Box (b) has length 50 cm, breadth 50 cm, and height 50 cm. Show your working.

May 8, 2026Mathematics

ScanSolve AI Answer

May 8, 2026

Answer

60 $cm, breadth$ b_a = 40 $cm, and height$ h_a = 50$ cm.

Hey Tanya, good to see you again.

1. Which box requires the lesser amount of material to make?

Step 1: Calculate the total surface area (TSA) of Box (a). Box (a) has length $l_a = 60$ cm, breadth $b_a = 40$ cm, and height $h_a = 50$ cm. The formula for the total surface area of a cuboid is $2(lb + bh + hl)$ . $TSA_a = 2(60 \times 40 + 40 \times 50 + 50 \times 60)$

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Asked on May 8, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on May 8, 2026

Hey Tanya, good to see you again. 1. Which box requires the lesser amount of material to make? Step 1: Calculate the total surface area (TSA) of Box (a). Box (a) has length l_a = 60 cm, breadth b_a = 40 cm, and height h_a = 50 cm. The formula for the total surface area of a cuboid is 2(lb + bh + hl). TSA_a = 2(60 × 40 + 40 × 50 + 50 × 60) TSA_a = 2(