The problem states that (3)/(4) of the money is 36000 frs.

The problem states that $\frac{3}{4}$ of the money is $36000 \text{ frs}$.
So, we can write the equation:

Multiply both sides by $\frac{4}{3}$:

All of the money is worth $\boxed{48000 \text{ frs}}$.

17.

The number is 3.256.

The first three significant figures are 3, 2, and 5.
The digit after the third significant figure (5) is 6. Since $6 \ge 5$, we round up the third significant figure.
So, 5 becomes 6.
The number 3.256 correct to 3 significant figures is $\boxed{3.26}$.

18.

The value is $\boxed{51}$.

19.

Principal ($P$) = $72000 \text{ frs}$
Rate ($R$) = $8\%$ per annum = 0.08
Time ($T$) = $2 \text{ years}$

$I = P \times R \times T$.

The simple interest is $\boxed{11520 \text{ frs}}$.

20.

Diameter ($d$) = $14 \text{ cm}$

$C = \pi d$.
Using $\pi \approx \frac{22}{7}$:

The circumference is $\boxed{44 \text{ cm}}$.

21.

Divide both the numerator and the denominator by their greatest common divisor.
Both 75 and 1000 are divisible by 25.

So, the fraction in its lowest terms is $\frac{3}{40}$.
0.075 as a fraction in its lowest term is $\boxed{\frac{3}{40}}$.

22.

The value is $\boxed{576}$.

23.

Average of 3 numbers = 45
Number of values = 3

Sum = Average $\times$ Number of values.

The sum of the three numbers is $\boxed{135}$.

24.

Total volume of kerosene = $20 \text{ liters}$
Total price = $700 \text{ frs}$

The price per liter was $\boxed{35 \text{ frs}}$.

25.

Spent on food = $\frac{3}{5}$
Spent on rent = $\frac{1}{10}$
Total spent = $\frac{3}{5} + \frac{1}{10}$
To add these fractions, find a common denominator, which is 10.

Total spent = $\frac{6}{10} + \frac{1}{10} = \frac{7}{10}$

The whole salary is represented by 1.
Fraction left = $1 - \text{Total spent}$

The fraction left for other things is $\boxed{\frac{3}{10}}$.

26.

The number is 72,295.

The number is Seventy-two thousand, two hundred ninety-five.
In words, 72,295 is $\boxed{\text{Seventy-two thousand, two hundred ninety-five}}$.

27.

The number is 2.503.

In the number 2.503:
2 is in the units place.
5 is in the tenths place.
0 is in the hundredths place.
3 is in the thousandths place.
The value of 5 in the number is $\boxed{5 \text{ tenths}}$ or $\boxed{0.5}$.

28.

Perimeter ($P$) = $24 \text{ m}$
Length ($L$) = $4 \text{ m}$

$P = 2(L + W)$, where $W$ is the width.

Divide both sides by 2:

Subtract 4 from both sides:

The width of the lawn is $\boxed{8 \text{ m}}$.

29.

Divide 65 by 5 repeatedly and record the remainders.
$65 \div 5 = 13$ remainder 0
$13 \div 5 = 2$ remainder 3
$2 \div 5 = 0$ remainder 2
Read the remainders from bottom to top: $230_5$.
So, $23 + 42$ in base 5 is $\boxed{230_5}$.

30.

Birth year = 1982
Age = $37 \text{ years}$

Peter will be 37 years old in the year $\boxed{2019}$.