We read your photo as:

Solve the following problems: 1. Calculate 0.018 of 200,000 frs. 2. Which is smaller, 1/4 or 7/8? Find their difference. 3. If X=5 and Y=3 1/2, calculate X-Y. 4. [Incomplete problem description]

Mathematics

ScanSolve AI Answer

Step-by-step solution

40 steps

Here are the solutions to the problems:

1.

  1. Set up a proportion based on the given information.

    0.05 of 200=100.05 \text{ of } 200 = 10

    This means 0.05×200=100.05 \times 200 = 10.

  2. Find the value of 0.018 of 200,000.

    0.018×200,0000.018 \times 200,000 =18×200= 18 \times 200 =3,600= 3,600

    The value of 0.018 of 200,000 frs is 3,600 frs\boxed{\text{3,600 frs}}.

    2.

  3. Identify the fractions.

    The fractions are 14\frac{1}{4} and 78\frac{7}{8}.

  4. Determine which fraction is smaller.

    To compare, find a common denominator, which is 8.
    14=1×24×2=28\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}
    Since 28<78\frac{2}{8} < \frac{7}{8}, 14\frac{1}{4} is the smaller fraction.

  5. Subtract the smaller fraction from the bigger one.

    78−14\frac{7}{8} - \frac{1}{4} =78−28= \frac{7}{8} - \frac{2}{8} =7−28= \frac{7 - 2}{8} =58= \frac{5}{8}

    The result is 58\boxed{\frac{5}{8}}.

    3.

  6. Write down the given values for X and Y.

    X=5X = 5 Y=312Y = 3\frac{1}{2}
  7. Convert Y to an improper fraction.

    Y=312=(3×2)+12=6+12=72Y = 3\frac{1}{2} = \frac{(3 \times 2) + 1}{2} = \frac{6 + 1}{2} = \frac{7}{2}
  8. Simplify X−YX - Y.

    X−Y=5−72X - Y = 5 - \frac{7}{2}
  9. Find a common denominator to subtract.

    5=5×22=1025 = \frac{5 \times 2}{2} = \frac{10}{2} X−Y=102−72X - Y = \frac{10}{2} - \frac{7}{2} =10−72= \frac{10 - 7}{2} =32= \frac{3}{2}

    The simplified value of X−YX - Y is 32\boxed{\frac{3}{2}}.

    4.

  10. List the given decimal fractions.

    0.045,0.371,0.3750.045, 0.371, 0.375
  11. Arrange them in ascending order of magnitude.

    Compare the numbers digit by digit from left to right.
    0.045 is the smallest because it has a 0 in the tenths place.
    Between 0.371 and 0.375, compare the thousandths place. 1<51 < 5.
    So, 0.371 is smaller than 0.375.
    The ascending order is 0.045,0.371,0.375\boxed{0.045, 0.371, 0.375}.

    5.

  12. Identify the average weight and the number of pigs.

    Average weight of 7 pigs = 35 kg35 \text{ kg}.
    Number of pigs = 7.

  13. Calculate the total weight.

    Total weight = Average weight ×\times Number of pigs

    =35 kg×7= 35 \text{ kg} \times 7 =245 kg= 245 \text{ kg}

    The total weight is 245 kg\boxed{245 \text{ kg}}.

    6.

  14. Determine the rate of time loss.

    A wall clock loses 2 minutes every three hours.

  15. Calculate how many 3-hour intervals are in 15 hours.

    Number of intervals = 15 hours3 hours/interval=5 intervals\frac{15 \text{ hours}}{3 \text{ hours/interval}} = 5 \text{ intervals}

  16. Calculate the total time lost.

    Total time lost = Loss per interval ×\times Number of intervals

    =2 minutes/interval×5 intervals= 2 \text{ minutes/interval} \times 5 \text{ intervals} =10 minutes= 10 \text{ minutes}

    The clock loses 10 minutes\boxed{10 \text{ minutes}} in 15 hours.

    7.

  17. Identify the decimals.

    The decimals are 0.124 and 2.5.

  18. Determine which decimal is smaller.

    0.124 is smaller than 2.5.

  19. Subtract the smaller decimal from the bigger one.

    2.5−0.1242.5 - 0.124

    To subtract, align the decimal points and add trailing zeros to 2.5:

    2.5002.500 −0.124-0.124

    −−−−−-----

    2.3762.376

    The result is 2.376\boxed{2.376}.

    8.

  20. Identify the cost of seven books.

    Seven books cost 2100 frs2100 \text{ frs}.

  21. Calculate the cost of one book.

    Cost per book = 2100 frs7 books=300 frs/book\frac{2100 \text{ frs}}{7 \text{ books}} = 300 \text{ frs/book}

  22. Calculate the number of books that can be bought with 900 frs900 \text{ frs}.

    Number of books = Total moneyCost per book\frac{\text{Total money}}{\text{Cost per book}}

    =900 frs300 frs/book= \frac{900 \text{ frs}}{300 \text{ frs/book}} =3 books= 3 \text{ books}

    The number of books that can be bought is 3\boxed{3}.

    9.

  23. Recall the conversion factor between grams and kilograms.

    1 kg=1000 g1 \text{ kg} = 1000 \text{ g}
  24. Convert 5400 g5400 \text{ g} to kilograms.

    5400 g=54001000 kg5400 \text{ g} = \frac{5400}{1000} \text{ kg} =5.4 kg= 5.4 \text{ kg}

    5400 g5400 \text{ g} is equal to 5.4 kg\boxed{5.4 \text{ kg}}.

    10.

  25. List the elements of sets A and B.

    A={3,6,9,12}A = \{3, 6, 9, 12\} B={6,8,10,12}B = \{6, 8, 10, 12\}
  26. Find the intersection of A and B, denoted as A∩BA \cap B.

    The intersection consists of elements that are common to both sets.
    Common elements are 6 and 12.

    A∩B={6,12}A \cap B = \{6, 12\}

    The intersection is {6,12}\boxed{\{6, 12\}}.

    11.

  27. Identify the numbers to be added in base 7.

    3447+2357344_7 + 235_7
  28. Add the numbers column by column from right to left, remembering that in base 7, digits range from 0 to 6.

    If a sum is 7 or more, divide by 7 to get the carry and the digit.

    Units column: 4+5=94 + 5 = 9.
    9÷7=19 \div 7 = 1 remainder 2. Write down 2, carry over 1.

    Sevens column: 4+3+1 (carry)=84 + 3 + 1 \text{ (carry)} = 8.
    8÷7=18 \div 7 = 1 remainder 1. Write down 1, carry over 1.

    Forty-nines column: 3+2+1 (carry)=63 + 2 + 1 \text{ (carry)} = 6.
    6÷7=06 \div 7 = 0 remainder 6. Write down 6.

    The sum is 6127\boxed{612_7}.

    12.

  29. Identify the initial amount and the ratio.

    Initial amount = 600 frs600 \text{ frs}.
    Ratio for increase = 5:45:4. This means the new amount is 54\frac{5}{4} of the original amount.

  30. Calculate the increased amount.

    Increased amount = Original amount ×54\times \frac{5}{4}

    =600 frs×54= 600 \text{ frs} \times \frac{5}{4} =600×54= \frac{600 \times 5}{4} =150×5= 150 \times 5 =750 frs= 750 \text{ frs}

    The increased amount is 750 frs\boxed{750 \text{ frs}}.

    13.

  31. Write the given equation.

    23=n18\frac{2}{3} = \frac{n}{18}
  32. Solve for nn by cross-multiplication.

    2×18=3×n2 \times 18 = 3 \times n 36=3n36 = 3n
  33. Divide by 3 to find nn.

    n=363n = \frac{36}{3} n=12n = 12

    The value of nn is 12\boxed{12}.

    14.

  34. Identify the given series.

    2,5,8,…2, 5, 8, \dots
  35. Determine the pattern.

    Find the difference between consecutive terms:
    5−2=35 - 2 = 3
    8−5=38 - 5 = 3
    The pattern is an arithmetic progression with a common difference of 3.

  36. Find the next number in the series.

    Add 3 to the last given term:

    8+3=118 + 3 = 11

    The next number in the series is 11\boxed{11}.

    15.

  37. List the numbers.

    3,8,24,13, 8, 24, 1
  38. Calculate the sum of these numbers.

    Sum = 3+8+24+1=363 + 8 + 24 + 1 = 36.
    The question states "The sum of 3, 8, 24 and 1 is 36." This confirms our sum.

  39. Count the number of values.

    There are 4 numbers.

  40. Calculate the average.

    Average = Sum of numbersNumber of values\frac{\text{Sum of numbers}}{\text{Number of values}}

    =364= \frac{36}{4} =9= 9

    The average of these numbers is 9\boxed{9}.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp