The problem you've provided is 22x - 4 x 3^x + 3 = 0. This equation involves two different bases (2 and 3) in the exponential terms, which makes it a transcendental equation. Such equati

The problem you've provided is $2^{2x} - 4 \times 3^x + 3 = 0$. This equation involves two different bases (2 and 3) in the exponential terms, which makes it a transcendental equation. Such equations are generally not solvable using elementary algebraic methods, except for specific values that can be found by inspection or numerical methods.

However, in typical algebra problems of this type, a common base is usually intended to allow for substitution and simplification into a quadratic equation. Given the structure of the problem and common curriculum, it is highly probable that the term $3^x$ was intended to be $2^x$, or $2^{2x}$ was intended to be $3^{2