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The question provides contradictory information for a single circle (if radius is 8 cm, diameter should be 16 cm; if diameter is 10 mm, radius should be 5 mm).
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3. Calculate the circumference of a circle with the radius and diameter .
The question provides contradictory information for a single circle (if radius is , diameter should be ; if diameter is , radius should be ). Therefore, we will calculate the circumference for two separate scenarios:
- Scenario 1: Using radius
The formula for the circumference of a circle using radius is .
Substitute the given radius.
$$ C = 2 \times \pi \times 8 \text{ cm} $$Calculate the circumference.
$$ C = 16\pi \text{ cm} $$ $$ C \approx 16 \times 3.14159 \text{ cm} $$ $$ C \approx 50.27 \text{ cm} $$ The circumference is $\boxed{16\pi \text{ cm}}$ or approximately $\boxed{50.27 \text{ cm}}$.- Scenario 2: Using diameter
Convert the diameter to centimeters for consistency ().
$$ d = 10 \text{ mm} = 1 \text{ cm} $$The formula for the circumference of a circle using diameter is .
Substitute the given diameter.
$$ C = \pi \times 1 \text{ cm} $$Calculate the circumference.
$$ C = \pi \text{ cm} $$ $$ C \approx 3.14159 \text{ cm} $$ $$ C \approx 3.14 \text{ cm} $$ The circumference is $\boxed{\pi \text{ cm}}$ or approximately $\boxed{3.14 \text{ cm}}$.4. Calculate the volume of a cylinder with base and height .
The formula for the volume of a cylinder is .
Substitute the given base area and height.
Calculate the volume.
The volume of the cylinder is .
5. Calculate the mode, median and mean of .
Order the data set from least to greatest.
There are data points.
Calculate the mode.
The mode is the value that appears most frequently. In this set, 133 appears twice and 138 appears twice.
The mode is .Calculate the median.
Since there is an even number of data points (), the median is the average of the two middle values (the 4th and 5th values).
The 4th value is 133.
The 5th value is 133.The median is .
Calculate the mean.
The mean is the sum of all values divided by the number of values.
The mean is .
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