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Determine the radius from the given diameter.

Mathematics

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Let's continue with these circle problems! We'll use the formula for the area of a circle A=πr2A = \pi r^2 and π=227\pi = \frac{22}{7}.

7. What is the area of a circle if the diameter is 7cm?

  1. Determine the radius from the given diameter.

    d=7 cmd = 7 \text{ cm} r=d2=72 cmr = \frac{d}{2} = \frac{7}{2} \text{ cm}
  2. Apply the area formula.

    A=πr2A = \pi r^2 A=227×(72 cm)2A = \frac{22}{7} \times \left(\frac{7}{2} \text{ cm}\right)^2 A=227×494 cm2A = \frac{22}{7} \times \frac{49}{4} \text{ cm}^2
  3. Simplify the expression.

    A=22×74 cm2A = \frac{22 \times 7}{4} \text{ cm}^2 A=1544 cm2A = \frac{154}{4} \text{ cm}^2 A=38.5 cm2A = 38.5 \text{ cm}^2

    The area of the circle is 38.5 cm2\boxed{\text{38.5 cm}^2}.

    8. The area of a circle is 2464cm2^2. Calculate its diameter to 2 sig. figures.

  4. Identify the given area and use the area formula to find the radius.

    A=2464 cm2A = 2464 \text{ cm}^2 A=πr2A = \pi r^2 2464 cm2=227r22464 \text{ cm}^2 = \frac{22}{7} r^2
  5. Solve for r2r^2 and then rr.

    r2=2464×722 cm2r^2 = \frac{2464 \times 7}{22} \text{ cm}^2 r2=1724822 cm2r^2 = \frac{17248}{22} \text{ cm}^2 r2=784 cm2r^2 = 784 \text{ cm}^2 r=784 cmr = \sqrt{784} \text{ cm} r=28 cmr = 28 \text{ cm}
  6. Calculate the diameter.

    d=2rd = 2r d=2×28 cmd = 2 \times 28 \text{ cm} d=56 cmd = 56 \text{ cm}
  7. Express the diameter to 2 significant figures.

    The diameter is already 56 cm, which has two significant figures.
    The diameter of the circle is 56 cm\boxed{\text{56 cm}}.

    9. Find the area of a semi circular field of diameter 20m.

  8. Determine the radius from the given diameter.

    d=20 md = 20 \text{ m} r=d2=20 m2=10 mr = \frac{d}{2} = \frac{20 \text{ m}}{2} = 10 \text{ m}
  9. Apply the formula for the area of a semi-circle.

    The area of a semi-circle is half the area of a full circle.

    Asemi=12πr2A_{semi} = \frac{1}{2} \pi r^2 Asemi=12×227×(10 m)2A_{semi} = \frac{1}{2} \times \frac{22}{7} \times (10 \text{ m})^2 Asemi=12×227×100 m2A_{semi} = \frac{1}{2} \times \frac{22}{7} \times 100 \text{ m}^2
  10. Simplify the expression.

    Asemi=117×100 m2A_{semi} = \frac{11}{7} \times 100 \text{ m}^2 Asemi=11007 m2A_{semi} = \frac{1100}{7} \text{ m}^2 Asemi≈157.14 m2A_{semi} \approx 157.14 \text{ m}^2

    The area of the semi-circular field is 157.14 m2\boxed{\text{157.14 m}^2}.

    10. What is the diameter of a circle whose area is 154cm2^2?

  11. Identify the given area and use the area formula to find the radius.

    A=154 cm2A = 154 \text{ cm}^2 A=πr2A = \pi r^2 154 cm2=227r2154 \text{ cm}^2 = \frac{22}{7} r^2
  12. Solve for r2r^2 and then rr.

    r2=154×722 cm2r^2 = \frac{154 \times 7}{22} \text{ cm}^2 r2=107822 cm2r^2 = \frac{1078}{22} \text{ cm}^2 r2=49 cm2r^2 = 49 \text{ cm}^2 r=49 cmr = \sqrt{49} \text{ cm} r=7 cmr = 7 \text{ cm}
  13. Calculate the diameter.

    d=2rd = 2r d=2×7 cmd = 2 \times 7 \text{ cm} d=14 cmd = 14 \text{ cm}

    The diameter of the circle is 14 cm\boxed{\text{14 cm}}.

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