The radius of a sphere is 10 cm. Find its surface area and volume. 2. The diameter of an iron ball is 6 cm. Find its surface area and volume (use pi = 3.14).

Given: $r = 10 \text{ cm}$.
Surface Area ($SA$) = $4\pi r^2$
Volume ($V$) = $\frac{4}{3}\pi r^3$

Using $\pi \approx 3.14159$:

Using $\pi \approx 3.14159$:

The surface area is $\boxed{\text{400\pi cm}^2 \text{ or approximately 1256.64 cm}^2}$ and the volume is $\boxed{\text{}\frac{4000}{3}\pi \text{ cm}^3 \text{ or approximately 4188.79 cm}^3}$.

2. The diameter of an iron ball is 6 cm. Find its surface area and volume (use $\pi = 3.14$).

Given: $d = 6 \text{ cm}$.
Radius $r = \frac{d}{2} = \frac{6 \text{ cm}}{2} = 3 \text{ cm}$.
Use $\pi = 3.14$.

The surface area is $\boxed{\text{113.04 cm}^2}$ and the volume is $\boxed{\text{113.04 cm}^3}$.

3. Find the formula for the surface area and volume of a sphere in terms of its diameter $d$.

The formula for surface area in terms of diameter is \boxed{\text{SA = \pi d^2}}.

The formula for volume in terms of diameter is \boxed{\text{V = \frac{1}{6}\pi d^3}}.