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Solve the following system of equations using the substitution method: 2x + 5y = 38 and 3x + 4y = 48.

Mathematics

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Answer

x=887,y=187x = \frac{88}{7}, y = \frac{18}{7}

Step-by-step solution

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Ili kutatua mfumo wa milinganyo kwa kutumia njia ya kubadilisha (substitution method), tutafuata hatua zifuatazo:

Milinganyo iliyotolewa ni:

  1. 2x+5y=382x + 5y = 38
  2. 3x+4y=483x + 4y = 48
  1. Tenga kigezo kimoja kutoka kwa mlinganyo mmoja.

    Tutatenga xx kutoka mlinganyo wa kwanza:

    2x+5y=382x + 5y = 38 2x=38−5y2x = 38 - 5y x=38−5y2x = \frac{38 - 5y}{2}
  2. Badilisha usemi huu wa xx katika mlinganyo wa pili.

    3(38−5y2)+4y=483\left(\frac{38 - 5y}{2}\right) + 4y = 48
  3. Tatua mlinganyo unaotokana kwa yy.

    Kuzidisha pande zote mbili za mlinganyo kwa 2 ili kuondoa sehemu:

    2⋅[3(38−5y2)+4y]=2⋅482 \cdot \left[3\left(\frac{38 - 5y}{2}\right) + 4y\right] = 2 \cdot 48 3(38−5y)+8y=963(38 - 5y) + 8y = 96 114−15y+8y=96114 - 15y + 8y = 96 114−7y=96114 - 7y = 96 −7y=96−114-7y = 96 - 114 −7y=−18-7y = -18 y=−18−7y = \frac{-18}{-7} y=187y = \frac{18}{7}
  4. Badilisha thamani ya yy uliyopata katika usemi wa xx kutoka Hatua ya 1.

    x=38−5(187)2x = \frac{38 - 5\left(\frac{18}{7}\right)}{2} x=38−9072x = \frac{38 - \frac{90}{7}}{2}

    Ili kurahisisha nambari, tunapata denominator ya kawaida:

    x=38×77−9072x = \frac{\frac{38 \times 7}{7} - \frac{90}{7}}{2} x=2667−9072x = \frac{\frac{266}{7} - \frac{90}{7}}{2} x=266−9072x = \frac{\frac{266 - 90}{7}}{2} x=17672x = \frac{\frac{176}{7}}{2} x=1767×2x = \frac{176}{7 \times 2} x=17614x = \frac{176}{14}

    Rahisisha sehemu kwa kugawanya nambari na denominator kwa 2:

    x=887x = \frac{88}{7}

    Kwa hiyo, suluhisho la mfumo wa milinganyo ni:

    x=887,y=187x = \frac{88}{7}, y = \frac{18}{7}
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