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Solve the following system of equations: x + 3y = 6 and −x + 8y = 5

Mathematics

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Answer

x=3,y=1x=3, y=1

Step-by-step solution

5 steps
  1. Identify the system of equations.

    The given system of equations is:

    x+3y=6(1)x + 3y = 6 \quad \text{(1)} −x+8y=5(2)-x + 8y = 5 \quad \text{(2)}
  2. Add equation (1) and equation (2) to eliminate xx.

    (x+3y)+(−x+8y)=6+5(x + 3y) + (-x + 8y) = 6 + 5 x−x+3y+8y=11x - x + 3y + 8y = 11 11y=1111y = 11
  3. Solve for yy.

    y=1111y = \frac{11}{11} y=1y = 1
  4. Substitute the value of yy into equation (1) to solve for xx.

    x+3(1)=6x + 3(1) = 6 x+3=6x + 3 = 6
  5. Solve for xx.

    x=6−3x = 6 - 3 x=3x = 3

    The solution to the system of equations is:

    x=3,y=1x=3, y=1
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