This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Here are the solutions to the problems from the image. Question 41: The side of a square field is 40 cm. Find its perimeter and area. Step 1: Write the formulas for the perimeter and area of a square. For a square with side length s: Perimeter (P) = 4s Area (A) = s^2 Step 2: Substitute the given side length into the formulas. Given s = 40 cm. Perimeter: P = 4 × 40 cm Area: A = (40 cm)^2 Step 3: Calculate the perimeter and area. Perimeter: P = 160 cm Area: A = 1600 cm^2 The perimeter of the square is 160 cm and the area is 1600 cm^2. --- Question 42: A rectangle has a length of 9 cm and a breadth of 8 cm. Find its perimeter and area. Step 1: Write the formulas for the perimeter and area of a rectangle. For a rectangle with length l and breadth b: Perimeter (P) = 2(l + b) Area (A) = l × b Step 2: Substitute the given values into the formulas. Given l = 9 cm and b = 8 cm. Perimeter: P = 2(9 cm + 8 cm) Area: A = 9 cm × 8 cm Step 3: Calculate the perimeter. P = 2(17 cm) P = 34 cm Step 4: Calculate the area. A = 72 cm^2 The perimeter of the rectangle is 34 cm and the area is 72 cm^2. That's 2 down. 3 left today — send the next one.