The side of a square field is 40 cm. Find its perimeter and area. A rectangle has a length of 9 cm and a breadth of 8 cm. Find its perimeter and area.

For a square with side length $s$:
Perimeter ($P$) = $4s$
Area ($A$) = $s^2$

Given $s = 40 \text{ cm}$.
Perimeter:

Area:

Perimeter:

Area:

The perimeter of the square is $\boxed{\text{160 cm}}$ and the area is $\boxed{\text{1600 cm}^2}$.

For a rectangle with length $l$ and breadth $b$:
Perimeter ($P$) = $2(l + b)$
Area ($A$) = $l \times b$

Given $l = 9 \text{ cm}$ and $b = 8 \text{ cm}$.
Perimeter:

Area:

The perimeter of the rectangle is $\boxed{\text{34 cm}}$ and the area is $\boxed{\text{72 cm}^2}$.