We read your photo as:

What is the size of the angle marked x in the diagram below? A. 145° B. 110° C. 90° D. 55° E. 45°

Mathematics

ScanSolve AI Answer

Answer

D

Step-by-step solution

20 steps

Here are the solutions to your questions, Ozoemena!

43. Hr min sec
12 15 30
7 35 21
-------
8 2 50 51

Assuming this question asks for the sum of the two time durations:

  1. Add the seconds.

    30 sec+21 sec=51 sec30 \text{ sec} + 21 \text{ sec} = 51 \text{ sec}

  2. Add the minutes.

    15 min+35 min=50 min15 \text{ min} + 35 \text{ min} = 50 \text{ min}

  3. Add the hours.

    12 hr+7 hr=19 hr12 \text{ hr} + 7 \text{ hr} = 19 \text{ hr}

  4. Combine the results.

    The sum is 19 hr 50 min 51 sec\boxed{\text{19 hr 50 min 51 sec}}.
    (Note: The numbers written below the line in your image, "8 2 50 51", do not match the correct sum for hours.)

    44. A village decides to build a school hall. Each man in the village has to pay N2 and each woman 50kobo. The total amount collected is N1320. If there are 520 men in the village, how many women are there?

  5. Calculate the total money contributed by men.

    Money from men=520 men×N2.00/man=N1040.00\text{Money from men} = 520 \text{ men} \times \text{N}2.00/\text{man} = \text{N}1040.00

  6. Calculate the total money contributed by women.

    Money from women=Total collected−Money from men\text{Money from women} = \text{Total collected} - \text{Money from men} Money from women=N1320.00−N1040.00=N280.00\text{Money from women} = \text{N}1320.00 - \text{N}1040.00 = \text{N}280.00

  7. Calculate the number of women.

    Since 50 kobo is N0.50:

    Number of women=Money from womenContribution per woman=N280.00N0.50=560\text{Number of women} = \frac{\text{Money from women}}{\text{Contribution per woman}} = \frac{\text{N}280.00}{\text{N}0.50} = 560

    The correct option is D.

    45. What is the volume of a rectangular water tank which is 8 meters long, 4 meters wide and 3 meters high?

  8. Recall the formula for the volume of a rectangular tank.

    Volume=length×width×height\text{Volume} = \text{length} \times \text{width} \times \text{height}

  9. Substitute the given dimensions.

    Volume=8 m×4 m×3 m\text{Volume} = 8 \text{ m} \times 4 \text{ m} \times 3 \text{ m}

  10. Calculate the volume.

    Volume=32 m2×3 m=96 m3\text{Volume} = 32 \text{ m}^2 \times 3 \text{ m} = 96 \text{ m}^3

    The correct option is C.

    46. The average attendance at a school for 5 days was 264. The attendance on 4 of those days were 239, 247, 277, and 239. What was the attendance on the fifth day?

  11. Calculate the total attendance for 5 days.

    Total attendance for 5 days=Average attendance×Number of days\text{Total attendance for 5 days} = \text{Average attendance} \times \text{Number of days} Total attendance for 5 days=264×5=1320\text{Total attendance for 5 days} = 264 \times 5 = 1320

  12. Calculate the total attendance for the 4 given days.

    Total attendance for 4 days=239+247+277+239=1002\text{Total attendance for 4 days} = 239 + 247 + 277 + 239 = 1002

  13. Calculate the attendance on the fifth day.

    Attendance on 5th day=Total attendance for 5 days−Total attendance for 4 days\text{Attendance on 5th day} = \text{Total attendance for 5 days} - \text{Total attendance for 4 days} Attendance on 5th day=1320−1002=318\text{Attendance on 5th day} = 1320 - 1002 = 318

    The calculated attendance on the fifth day is 318\boxed{318}.
    (Note: This answer is not among the provided options.)

    47. Add up 20kg, 800kg, 1.2kg and 450g. Write your answer in kg.

  14. Convert all measurements to kilograms (kg).

    • 20 kg
    • 800 kg
    • 1.2 kg
    • 450 g = 4501000\frac{450}{1000} kg = 0.45 kg

  15. Add all the values in kilograms.

    20 kg+800 kg+1.2 kg+0.45 kg=821.65 kg20 \text{ kg} + 800 \text{ kg} + 1.2 \text{ kg} + 0.45 \text{ kg} = 821.65 \text{ kg}

    (Note: If "800kg" was a typo and meant to be "800g", then the sum would be 20 kg+0.8 kg+1.2 kg+0.45 kg=22.45 kg20 \text{ kg} + 0.8 \text{ kg} + 1.2 \text{ kg} + 0.45 \text{ kg} = 22.45 \text{ kg}, which matches option B. Assuming this typo, the answer is 22.45 kg.)
    The correct option is B.

    48. A decagon is a polygon with ____ sides.

  16. Recall the definition of a decagon.

    A decagon is a polygon with ten sides.
    The correct option is D.

    49. What is the size of the angle marked x in the diagram below?

  17. Recognize that angles on a straight line sum to 180∘180^\circ.

    The angles 35∘35^\circ and xx form a linear pair.

  18. Set up the equation and solve for xx.

    x+35∘=180∘x + 35^\circ = 180^\circ x=180∘−35∘x = 180^\circ - 35^\circ x=145∘x = 145^\circ

    The correct option is A.

    50. Write MCMIX in ordinary numeral.

  19. Break down the Roman numeral into its components.

    • M = 1000
    • CM = 900 (C before M means 1000−1001000 - 100)
    • IX = 9 (I before X means 10−110 - 1)

  20. Sum the values.

    MCMIX=1000+900+9=1909\text{MCMIX} = 1000 + 900 + 9 = 1909

    The correct option is B.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question

More Mathematics Questions

QSolve for x in the given geometric diagram, where angles are marked as 75°, 65°, 70°, and x°.QDraw angles with the following degree measures: a. 140° b. 82° c. 195° d. 70° e. 35°. 2. Estimate…QGiven Angle D = x^ + 60^.QGiven that cos(2x+15°)=sin(x−30°), 0≤x≤90°, find the value of x. In the diagram, ABCF is a straight…QDetermine, with reasons, the following angles in terms of x: D1, D2, D3, D4, D5.
See all Mathematics questions →
Got a syllabus? Photograph it and I'll tell you what's due and what's worth the most.
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp