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The table shows the number of calls received by a call centre in a day. Calculate the mean number of calls per day.

Mathematics

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Answers

3 parts
a(i)

31-40\text{31-40}

a(ii)

15\text{15}

b

39.53\text{39.53}

Step-by-step solution

9 steps

I've interpreted the table and questions from your image.

Here is the data from the table:

Number of calls per day (Class Interval)Frequency (ff)Midpoint (xx)fxfx
1-1045.522.0
11-20815.5124.0
21-301225.5306.0
31-401535.5532.5
41-501045.5455.0
51-60755.5388.5
61-70565.5327.5
71-80375.5226.5
81-90285.5171.0
91-100195.595.5
Total∑f=67\sum f = 67∑fx=2648.5\sum fx = 2648.5

Part a(i)· 2 steps

State the modal class.

From the table above

  1. Identify the highest frequency in the table.

    The highest frequency is 15.

  2. Identify the class interval corresponding to the highest frequency.

    The class interval corresponding to a frequency of 15 is 31-40.
    The modal class is 31-40\boxed{\text{31-40}}.

Part a(ii)

15\text{15}

State the modal frequency.

  1. Identify the highest frequency in the table.

    The highest frequency is 15.
    The modal frequency is 15\boxed{\text{15}}.

Part b

39.53\text{39.53}

Use the table above to calculate the mean of the number of calls per day.

  1. Calculate the midpoint (xx) for each class interval.

    The midpoint is calculated as (lower limit + upper limit) / 2. These are shown in the table above.

  2. Calculate the product of frequency and midpoint (fxfx) for each class interval.

    These values are shown in the table above.

  3. Calculate the sum of all frequencies (∑f\sum f).

    ∑f=4+8+12+15+10+7+5+3+2+1=67\sum f = 4 + 8 + 12 + 15 + 10 + 7 + 5 + 3 + 2 + 1 = 67
  4. Calculate the sum of all fxfx values (∑fx\sum fx).

    ∑fx=22.0+124.0+306.0+532.5+455.0+388.5+327.5+226.5+171.0+95.5=2648.5\sum fx = 22.0 + 124.0 + 306.0 + 532.5 + 455.0 + 388.5 + 327.5 + 226.5 + 171.0 + 95.5 = 2648.5
  5. Use the formula for the mean of grouped data.

    The mean (xˉ\bar{x}) is given by:

    xˉ=∑fx∑f\bar{x} = \frac{\sum fx}{\sum f} xˉ=2648.567\bar{x} = \frac{2648.5}{67} xˉ≈39.52985\bar{x} \approx 39.52985
  6. Round the mean to an appropriate number of decimal places (e.g., two decimal places).

    xˉ≈39.53\bar{x} \approx 39.53

    The mean of the number of calls per day is 39.53\boxed{\text{39.53}}.

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