This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Thanks for sending the image again with the clearer view of the table! Now I can answer Question 7.
Here are the solutions based on the provided table:
Question 7:
a) How many articles were sold in the week? Step 1: Calculate the total number of watches sold. Step 2: Calculate the total number of rings sold. Step 3: Calculate the total number of brooches sold. Step 4: Sum the totals for all articles. A total of were sold in the week.
b) On which day were the most articles sold? Step 1: Calculate the total articles sold for each day. Step 2: Identify the day with the highest total. The highest total is 25, which occurred on Saturday. The most articles were sold on .
c) How many rings and brooches were sold on Friday and Saturday? Step 1: Find the number of rings sold on Friday and Saturday. Step 2: Find the number of brooches sold on Friday and Saturday. Step 3: Sum these values. Total Rings and Brooches (Friday & Saturday) = 9 + 10 + 8 + 7 = 34 A total of were sold on Friday and Saturday.
d) Which were sold most in the week: rings, brooches or watches? Step 1: Recall the total sales for each type of article from part (a). Step 2: Compare the totals. The highest total is 39, which corresponds to rings. were sold most in the week.
e) When were the fewest articles sold? Step 1: Recall the total articles sold for each day from part (b). Step 2: Identify the day with the lowest total. The lowest total is 7, which occurred on Monday. The fewest articles were sold on .
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Thanks for sending the image again with the clearer view of the table! Now I can answer Question 7.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.