There are 40 students. 12 brought a pen, pencil, and ruler. 5 brought none of these. How many students brought at least one instrument?

here are the solutions to the math problems. ITEM 1 Let P represent students who brought a pen, C for pencil, and R for ruler. Total students = 40. Students who brought all 3 instruments: |P ∩ C ∩ R| = 12. Students who didn't have any instrument: |(P ∪ C ∪ R)'| = 5. So, students who had at least one instrument: |P ∪ C ∪ R| = 40 − 5 = 35. From the given information, we can deduce the number of students who had only one type of instrument or only two types. Let's denote the number of

There are 40 students. 12 brought a pen, pencil, and ruler. 5 brought none of these. How many students brought at least one instrument?

here are the solutions to the math problems. ITEM 1 Let P represent students who brought a pen, C for pencil, and R for ruler. Total students = 40. Students who brought all 3 instruments: |P ∩ C ∩ R| = 12. Students who didn't have any instrument: |(P ∪ C ∪ R)'| = 5. So, students who had at least one instrument: |P ∪ C ∪ R| = 40 − 5 = 35. From the given information, we can deduce the number of students who had only one type of instrument or only two types. Let's denote the number of

Solved: There are 40 students. 12 brought a pen, pencil…

here are the solutions to the math problems.

ITEM 1
Let P represent students who brought a pen, C for pencil, and R for ruler.
Total students = 40.
Students who brought all 3 instruments: $|P \cap C \cap R| = 12$ .
Students who didn't have any instrument: $|(P \cup C \cup R)'| = 5$ .
So, students who had at least one instrument: $|P \cup C \cup R| = 40 - 5 = 35$ .

From the given information, we can deduce the number of students who had only one type of instrument or only two types. Let's denote the number of

There are 40 students. 12 brought a pen, pencil, and ruler. 5 brought none of these. How many students brought at least one instrument?

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