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There are two questions in the provided text. Mrs Wulu claims that if she leaves Jansenville at 7:00 am, she will reach Port Shepstone at 11:30 if she includes 20 minutes for stop and go. Show whether

Mathematics

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4.1.4 Mrs Wulu claims that if she leaves Jansenville at 7:00 am, she will reach Port Shepstone at 11:30 if she includes 20 minutes for stop and go. Show whether her claim is CORRECT or NOT.

This question cannot be answered as there is missing information. To determine if Mrs Wulu's claim is correct, we would need to know the actual travel time required to get from Jansenville to Port Shepstone without stops. Without this information, we cannot verify her claim.

Cannot be determined due to missing information.\boxed{\text{Cannot be determined due to missing information.}}

4.2.1 Determine the diameter the cylinder

  1. Identify the given radius.

    The radius (rr) of the cylinder is 4 cm.

  2. Use the formula for diameter.

    The diameter (DD) is twice the radius: D=2×rD = 2 \times r.

    D=2×4 cmD = 2 \times 4 \text{ cm} D=8 cmD = 8 \text{ cm} 8 cm\boxed{\text{8 cm}}

    4.2.2 If the formula to calculate the volume of a cylinder is V=π×r×rV = \pi \times r \times r, where π=3.142\pi = 3.142, determine the volume of a cylinder in m3\text{m}^3.

    Note: The formula provided, V=π×r×rV = \pi \times r \times r, is for the area of a circle. For the volume of a cylinder, the height (hh) must be included. We will proceed using the standard volume formula for a cylinder, V=π×r×r×hV = \pi \times r \times r \times h, as the diagram clearly shows a height.

  3. Identify the given values and the correct formula.

    Radius (rr) =4= 4 cm
    Height (hh) =9= 9 cm
    π=3.142\pi = 3.142
    Volume of a cylinder (VV) =πr2h= \pi r^2 h

  4. Convert the radius and height from centimeters to meters.

    1 m=100 cm1 \text{ m} = 100 \text{ cm}

    r=4 cm=4100 m=0.04 mr = 4 \text{ cm} = \frac{4}{100} \text{ m} = 0.04 \text{ m} h=9 cm=9100 m=0.09 mh = 9 \text{ cm} = \frac{9}{100} \text{ m} = 0.09 \text{ m}
  5. Substitute the values into the volume formula.

    V=3.142×(0.04 m)2×(0.09 m)V = 3.142 \times (0.04 \text{ m})^2 \times (0.09 \text{ m}) V=3.142×(0.0016 m2)×(0.09 m)V = 3.142 \times (0.0016 \text{ m}^2) \times (0.09 \text{ m}) V=3.142×0.000144 m3V = 3.142 \times 0.000144 \text{ m}^3
  6. Calculate the volume.

    V=0.000452448 m3V = 0.000452448 \text{ m}^3 0.000452448 m3\boxed{\text{0.000452448 m}^3}
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