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If the plane leaves OR Tambo International airport at 09H40, at what time will it arrive in Cape Town? 6.2. Calculate the speed at which the plane will be travelling?

Mathematics

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2 parts
6.1

11H50\text{11H50}

6.2

584.31 km/h\text{584.31 km/h}

Step-by-step solution

5 steps

Part 6.1· 2 steps

  1. Identify the departure time and flight duration.

    The plane leaves at 09H4009\text{H}40.
    The flight takes 2 hours 10 minutes.

  2. Add the flight duration to the departure time.

    Add the hours: 09+2=1109 + 2 = 11 hours.
    Add the minutes: 40+10=5040 + 10 = 50 minutes.

    The arrival time will be 11H5011\text{H}50.

    The plane will arrive in Cape Town at 11H50\boxed{\text{11H50}}.

Part 6.2

584.31 km/h\text{584.31 km/h}

  1. Convert the flight duration to hours.

    The flight duration is 2 hours 10 minutes.
    To convert minutes to hours, divide by 60.

    10 minutes=1060 hours=16 hours≈0.1667 hours10 \text{ minutes} = \frac{10}{60} \text{ hours} = \frac{1}{6} \text{ hours} \approx 0.1667 \text{ hours}

    Total time in hours:

    Time=2+1060 hours=2+16 hours=126+16 hours=136 hours\text{Time} = 2 + \frac{10}{60} \text{ hours} = 2 + \frac{1}{6} \text{ hours} = \frac{12}{6} + \frac{1}{6} \text{ hours} = \frac{13}{6} \text{ hours} Time≈2.1667 hours\text{Time} \approx 2.1667 \text{ hours}

  2. Identify the distance.

    The distance from Johannesburg to Cape Town is 1266 km1266 \text{ km}.

  3. Calculate the speed using the formula Speed=DistanceTime\text{Speed} = \frac{\text{Distance}}{\text{Time}}.

    Speed=1266 km136 hours\text{Speed} = \frac{1266 \text{ km}}{\frac{13}{6} \text{ hours}} Speed=1266×613 km/h\text{Speed} = \frac{1266 \times 6}{13} \text{ km/h} Speed=759613 km/h\text{Speed} = \frac{7596}{13} \text{ km/h} Speed≈584.31 km/h\text{Speed} \approx 584.31 \text{ km/h}

    The speed at which the plane will be travelling is approximately 584.31 km/h\boxed{\text{584.31 km/h}}.

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