This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Step 1: Identify the departure and arrival times and locations. Tsotsoma departed from Johannesburg at 10:00 on 26 June 2021. Tsotsoma arrived in Paris at 20:00 on 26 June 2021. Step 2: Determine the time difference between Johannesburg and Paris, considering Daylight Saving Time (DST). Johannesburg observes South African Standard Time (SAST), which is UTC+2. Paris observes Central European Time (CET), which is UTC+1. However, the problem states that Paris practices DST. On 26 June 2021, Paris would be observing Central European Summer Time (CEST), which is UTC+2. Since both Johannesburg (SAST) and Paris (CEST) are UTC+2 on this date, there is no time difference between the two cities. Step 3: Calculate the flying time. Since there is no time difference between Johannesburg and Paris on this specific date, the flying time can be calculated by directly subtracting the departure time from the arrival time. Flying time = Arrival time - Departure time Flying time = 20:00 - 10:00 Flying time = 10 hours The flying time from Johannesburg to Paris is 10 hours. 10 hours Send me the next one 📸