Solve this using surds rule √12/121

Find the largest perfect square factor of 12. The factors of 12 are 1, 2, 3, 4, 6, 12. The largest perfect square factor is 4.

$$\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3}$$

$$\frac{\sqrt{12}}{\sqrt{121}} = \frac{2\sqrt{3}}{11}$$

The simplified form is:

$$\frac{2\sqrt{3}}{11}$$