If tan theta = sqrt(3), find (i) the size of theta (ii) sin theta

We are given $\tan \theta = \sqrt{3}$. To find $\theta$, we take the inverse tangent of both sides.

$$\theta = \arctan(\sqrt{3})$$

We know that $\tan(60^\circ) = \sqrt{3}$.

$$\theta = 60^\circ$$

The size of angle $\theta$ is $\boxed{\text{60}^\circ}$.

Now that we know $\theta = 60^\circ$, we need to find $\sin(60^\circ)$.

$$\sin \theta = \sin(60^\circ)$$

The value of $\sin(60^\circ)$ is a standard trigonometric value.

$$\sin(60^\circ) = \frac{\sqrt{3}}{2}$$

The value of $\sin \theta$ is $\boxed{\frac{\sqrt{3}}{2}}$.